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3 years ago

5

Determine the solution using substitution y=3/2x-6 2y=7-4x

2 answers:

Vika [28.1K]3 years ago

6 0

Answer:

x = 19/7 , y= -27/14

Step-by-step explanation:

ira [324]3 years ago

4 0

(19/7, -27/14) x= 19/7 y=-27/14

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In the equation 8x - 1=3x+4 the variable x represents the same value. Which value of x is the solution of the equation x = 0 1 2

OleMash [197]

the AnSwEr is

12 because 8x - 1=3x+4 the variable x represents the same value and x= 0

7 0

3 years ago

7(6m - 4) = -364 pls try and show work thanks!

quester [9]

Answer:

7(6m - 4) = -364

multiply 7 for both variables in the parenthesis

42m - 28 = -364

move 28 to other side

42m= -336

divide 42 on both sides

m= -8

3 0

2 years ago

Read 2 more answers

Every positive real number has a positive and a negative square root, the ________ root is called the principal root. *

fomenos

9514 1404 393

Answer:

B) positive

Step-by-step explanation:

For even-index roots, which may be either positive or negative, the <u> </u><u><em>positive</em></u><u> </u> root is called the principal root.

5 0

2 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

2 years ago

Franco read 3/8 of a chapter of his history book in 1/5 of an hour. At this rate, how many chapters of his history book can he r

Irina18 [472]

He can read $1\frac{7}{8}$ chapters of his history book in 1 hour.

<em><u>Explanation</u></em>

Franco read 3/8 of a chapter of his history book in 1/5 of an hour.

Suppose, he can read $x$ chapters of his book in 1 hour at this rate.

So, the equation according to the <u>ratio of 'the chapter to the time'</u> will be....

$\frac{x}{1}= \frac{\frac{3}{8}}{\frac{1}{5}}\\ \\ \frac{x}{1}=\frac{3}{8}*\frac{5}{1}\\ \\ \frac{x}{1}=\frac{15}{8} \\ \\ x= \frac{15}{8}= 1\frac{7}{8}$

So, he can read $1\frac{7}{8}$ chapters of his history book in 1 hour.

6 0

3 years ago