Answer:
Yes
Step-by-step explanation:
Answer:
Step-by-step explanation:
<h3>Part B</h3>
Assumed the dimensions of the top and bottom parts are identical.
Since the cylindrical part has total height of 1.8 cm and the hemisphere volume is transferred to bottom part and the cone part is still full, the value of h is the difference of the total height of cylinder and full part of the top section of cylinder:
- h = 1.8 cm - 0.3 cm = 1.5 cm
<h3>Part C</h3>
Find the volume of sand in the bottom part. It consists of a hemisphere and a cylinder of 1.5 cm height.
- V(cylinder) = πr²h = 3.14*(2.6/2)²*1.5 ≈ 7.96 cm³
- V(hemisphere) = 2/3πr³ = 2/3*3.14*(2.6/2)³ ≈ 4.6 cm³
<u>Total sand in the bottom part:</u>
<u>Time taken:</u>
- 12.56 / 0.05 = 251.2 seconds = 4 min 11.2 seconds
Answer:
an unbroken part of a circle consisting of two points on the circle called the endpoints and all the points of the circle between them. arc. an arc of a circle whose points are on or in the interior of a central angle.
The first step to take is to plot the coordinates of the figure. Next, we caculate the distances of the sides of the polygon using distance formula given the coordinates of points. Next we get the midpoint of each side and connect them to each other. we calculate again the distances. The resulting figure is composed of four congruent sides but the angles are not perpendicular. The answer is D. rhombus
Hello!
Recall that:
![\sqrt[z]{x^{y} }](https://tex.z-dn.net/?f=%5Csqrt%5Bz%5D%7Bx%5E%7By%7D%20%7D)
is equal to 
. Therefore:
![\sqrt[3]{x^{2} } = x^{\frac{2}{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%20%7D%20%3D%20x%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:
