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3 years ago

Plz i need helpPlzzzzz I need help

Mathematics

1 answer:

Klio2033 [76]3 years ago

6 0

Answer:

51%

Step-by-step explanation:

Add up the tallies, as follows: 17+24+9+19. Then divide the "cycling" tally (24) by this sum ( 69), obtaining the "observed probability that the customer will want to cycle"): p = 24/69 = 34.7%.

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The length of a rectangle is 10 more than the width. If the

kotegsom [21]

Answer:

Dimensions : L = 12 inches, Width = 2 inches

Step-by-step explanation:

Let width be w

Let length be w + 10

Area = length x width

24 = w x (w + 10)

$24 = w^2 + 10w\\\\w^2 + 10w - 24 = 0\\\\w^2 +12w -2w -24 = 0\\\\w(w+12) -2(w+12) = 0\\(w-2)(w+12)=0 \\w = 2 , -12$

Since width is a side of a rectangle , it cannot be negative. so w = 2 inches .

Therefore , length = w + 10 = 12inches

5 0

3 years ago

How to write 5,484.366 in expanded form

Flauer [41]

5,000+400+80+4+.3+.06+.006

8 0

3 years ago

According to the table below, what is the domain of the data?

maxonik [38]

Answer:

796037854

Step-by-step explanation:

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3 0

3 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

3 years ago

It took Debbie 3.6 hours to drive to her mother's house on Thursday morning. On her return trip on Friday night, traffic was hea

Mrac [35]

Answer:

36 mph

Step-by-step explanation:

d = rt

d = (x)(3.6)

d = (x-4)(4)

3.6x = 4x - 16

-0.4x = -16

x = 40

Her speed was 40 on Thursday, so 36 on Friday

7 0

3 years ago