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Lemur [1.5K]
2 years ago
12

Write the equation of a line perpendicular to y = 1/3x - 9 that passes through the point (-6, 10)

Mathematics
1 answer:
castortr0y [4]2 years ago
7 0

Answer:

B

y = -3x - 8

Step-by-step explanation:

the product of the slopes of two perpendicular lines is -1

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A man invests his savings in two accounts ,one paying6% and the other paying 10% simple interest per year. He puts twice as much
AnnyKZ [126]

Answer: he invested $46062.5 at 6% and $23031.25 at 10%

Step-by-step explanation:

Let x represent the amount which he invested in the account paying 6% interest.

Let y represent the amount which he invested in the account paying 10% interest.

He puts twice as much in the lower-yielding account because it is less risky.. This means that

x = 2y

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account paying 6% interest,

P = $x

T = 1 year

R = 6℅

I = (x × 6 × 1)/100 = 0.06x

Considering the account paying 10% interest,

P = $y

T = 1 year

R = 10℅

I = (y × 10 × 1)/100 = 0.1y

His annual interest is $7370dollars. it means that

0.06x + 0.2y = 7370 - - - - - - - - - -1

Substituting x = 2y into equation 1, it becomes

0.06 × 2y + 0.2y = 7370

0.12y + 0.2y = 7370

0.32y = 7370

y = 7370/0.32

y = $23031.25

x = 2 × 23031.25

x = 46062.5

6 0
3 years ago
Which of the following represents x =1/3y written in general form?
Serhud [2]

If you would like to write x = 1/3 * y in general form, you can do this using the following steps:

The general form of the equation is: ax + by + c = 0.

x = 1/3 * y

x - 1/3 * y = 0


The correct result would be x - 1/3 * y = 0.

4 0
3 years ago
Um I need help with thissss
Vladimir [108]

Answer:

its you again

Step-by-step explanation:

if they have the same amount of dashes on the same sided they are congruent

does that answer your question

6 0
3 years ago
Read 2 more answers
If ON = MN, find MN.
Furkat [3]
Use Pythagorean theorem.

[tex]|ON|^2+|MN|^2=|OM|^2\\\\x^2+x^2=8^2\\\\2x^2=64\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=32\to x=\sqrt{32}\\\\x=\sqrt{16\cdot2}\\\\x=\sqrt{16}\cdot\sqrt2\\\\\boxed{x=4\sqrt2}

Answer: |MN| = 4√2.
4 0
3 years ago
Algebraically prove that X^3+10/x^3+9=1+ 1/x^3+9 where x is not equal to -3
ehidna [41]
<span>Algebraically prove that X^3+10/x^3+9=1+ 1/x^3+9 where x is not equal to -3
</span>\dfrac{x^3+10}{x^3+9}=1+\dfrac{1}{x^3+9} \\ \\ \\  \dfrac{x^3+10}{x^3+9}=\dfrac{(x^3+9)+1}{x^3+9}\\ \\ \\  \dfrac{x^3+10}{x^3+9}=\dfrac{x^3+10}{x^3+9}  \\ \\ \\x\in R \qquad x\in (-\infty, +\infty)<span>
</span>
7 0
3 years ago
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