3 years ago

Solve for x 27^(2x+4)=1/9^(x-46)

1 answer:

8 0

$27^{2x+4}=(\frac{1}{9})^{x-46} \\
(3^3)^{2x+4}=(3^{-2})^{x-46} \\
3^{3(2x+4)}=3^{-2(x-46)} \\
3^{6x+12}=3^{-2x+92} \\
6x+12=-2x+92 \\
6x+2x=92-12 \\
8x=80 \\
x=10$

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