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kogti [31]
3 years ago
11

If g(x) = X² +3, find g(4)

Mathematics
2 answers:
elena55 [62]3 years ago
3 0

Answer:

g(4) = 19

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

Step-by-step explanation:

<u>Step 1: Define</u>

g(x) = x² + 3

g(4) is x = 4

<u>Step 2: Solve</u>

  1. Substitute:                    g(4) = 4² + 3
  2. Evaluate:                       g(4) = 16 + 3
  3. Add:                              g(4) = 19
Neporo4naja [7]3 years ago
3 0
No x-intercept/zero/no solution
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Step-by-step explanation:

If you are to assume the relationship is proportional then if he makes 10 liters in 2 days you divide 10 by 2 and you get 5. This means he makes 5 liters a day. Then you add 5 to 10 and you get 15 which means you are adding another day(5) So he needs to work an extra day which would give you three dyas total. Hope this helped!

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3 years ago
Trigonometry. This is an Tangent question.​
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Answer:

28/21

Step-by-step explanation:

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For an angle θ, tan(θ) is a negative number. Which quadrants might θ be in?
Klio2033 [76]

So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.  

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2 years ago
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3 years ago
What are the diameters of the painting?<br> Easy!!!
zalisa [80]

x = 10.22 in

Solution:

Width of the figure = x in

Length of the figure = (2x + 5) in

Area of the figure = 260 in²

<u>To find the value of x:</u>

<em>Area of the figure = length × width</em>

length × width = 260

(2x + 5) × x = 260

2x^2+5x=260

Subtract 260 from both sides of the equation.

2x^2+5x-260=0

Factor the above quadratic expression.

Quadratic equation formula:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

$x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 2(-260)}}{2 \cdot 2}

$x=\frac{-5 \pm \sqrt{2105}}{4}

$x=\frac{-5+\sqrt{2105}}{4}, \  x=\frac{-5-\sqrt{2105}}{4}

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Hence x = 10.22 in.

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