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Lera25 [3.4K]
3 years ago
5

Sally spelled 2 words incorrectly out of 20 spelling words on the test. What percent grade did Sally get on the test?

Mathematics
1 answer:
Tom [10]3 years ago
7 0

Answer:

90%

Step-by-step explanation:

So Sally gets 18/20 of the questions correct then you need to make the denominator of the fraction to 100 which makes a percent. So you multiply both the numerator and denominator by 5:

90/100

which is equal to 90%

Hope this helps!

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Pls help number 7<br> I need helpll
Novosadov [1.4K]

Answer:

The least common multiple is the smallest

Step-by-step explanation:

It is easy. Net time you can find math help on khan Academy.

7 0
3 years ago
Lin's father is paying for a $20 meal. He has a 30%-off coupon for the meal. After the discount, a 8% sales tax is applied.
Airida [17]

Answer:

15.12

Step-by-step explanation:

Cost of meal = $20

Discount (coupon) = 30%

Amount of discount = 30% of $20

= 30/100 * 20

= 0.3 * 20

= $6

Amount paid after discount= initial cost of meal - discount

= $20 -$6

= $14

Sales tax =8%

Amount of sales tax = 8% of $14

= 8/100 * 14

= 0.08 * 14

= $1.12

Total amount paid = Amount paid after discount + Amount of sales tax

= $14 + $1.12

= 15.12

8 0
2 years ago
Hey will give brainiest if correct
melisa1 [442]

3 inches i agree too 2020

5 0
3 years ago
Let a4+a8+a12+a16=224. Find the sum of first 19 term in sequence.
Tomtit [17]

Without knowing anything about the sequence, this is impossible to answer. But suppose the sequence is arithmetic, in which case each term differs by some constant k:

a_2=a_1+k

a_3=a_2+k=a_1+2k

a_4=a_3+k=a_1+3k

\ldots

a_n=a_{n-1}+k=a_1+(n-1)k

Then we can write

a_4+a_8+a_{12}+a_{16}=4a_1+36k=224\implies a_1+9k=56

and from the formula above, we see this means the 10th term in the sequence is a_{10}=56. But that's all the specific info we can gather about such an arithmetic sequence. If we set the first term to be some unknown a_1=a, then the sum of the first 19 terms in the sequence would be

\displaystyle\sum_{n=1}^{19}a_n=\sum_{n=1}^{19}\big(a+(n-1)k\big)=19a+k\sum_{n=1}^{18}n=19a+171k

If we knew one more term in the sequence, we could determine the value of k and derive the value of a (if the first term a_1 is not immediately given), and then go on to find an exact numeric value for the sum.

7 0
3 years ago
The ratio of working-age population to the elderly in the United States (including projections after 2000) is given by the funct
Dovator [93]

Answer:

a) Sketch the graph of the function f. (it is in the attached file)

b) What was the ratio at the beginning of 2006? At the beginning of 2014?

For 2006 the ratio is 3.92

For 2014 the ratio is 3.5

c) Over what years is the ratio constant?

[1995, 2000]

d) Over what years is the decline of the ratio greatest?

[2010, 2030]

Step-by-step explanation:

b) We first need to know in between which function 2006 falls into, so if we start in t=0=1995, then 2006-1995=11, t=11

t=11 fall into:

f(x)=-0.03t+4.25

f(11)=-0.03(11)+4.25=3.92

For 2006 the ratio is 3.92

2014:

Same process that 2006, t=0=1995, then 2014-1995=19, t=19

t=19fall into:

f(x)=-0.075t+4.925

f(19)=-0.075(11)+4.925=3.5

For 2014 the ratio is 3.5

c) The ratio is only constant in the first section of the graph 0≤t<5, since 4.1 is constant. Following the same process for the years in star (b) we have t=0, 1995+0=1995, t=5, 1995+5=2000.

The ratio will be constant between [1995, 2000]

d) For the greatest decline we need to compare slopes. From the line equation we have:

y(x)=mx+b where m is the slope and b is the point the line intersects with the y axis. Here we have:

f(x)=-0.03t+4.25  for 5≤t<15

f(x)=-0.075t+4.925  for 15≤t≤35

So:

m=-0.03 for 5≤t<15

m=-0.075 for 15≤t≤35

If we are measuring the steepness of the decline, we have to compare:

|-0.03| and |-0.075| or 0.03 and 0.075, easily finding that 0.075>0.03

And doing the sames process for the years in question (c):

t=15, 1995+15=2010, and t=35, 1995+35=2030

This means that the biggest decline is between the years:

[2010, 2030]

3 0
3 years ago
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