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Sphinxa [80]
3 years ago
9

12x 11 then add 1220

Mathematics
1 answer:
Butoxors [25]3 years ago
5 0

Answer:

1352

Step-by-step explanation:

NNNNNNNNNNNNNNNNNNNNNNNNNUUUUUUUUUUUUUUUUUUUUUUUUUUUUMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMBBBBBBBBBBBBBBBBBBBBBBBBBEEEEEEEEEEEEEEEEEEEERRRRRRRRRRRRRRRRRRSSSSSSSSSSSSSSSS

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The cubic polynomial below has a double root at r4 and one root at x = 6 and passes Through the point (2, 36) as shown. Algebrai
qaws [65]

The graph in the question is missing.

Answer:

y  = \frac{-1}{4}( x^3 + 2x^2 - 32x -96)

Step-by-step explanation:

The function is cubic

It has roots as -4, -4 , 6

this means the value of x = -4, -4 , 6 which makes the entire equation zero

so we have solutions as

x+4 = 0

x+4 = 0

x- 6 = 0

on forming a cubic equation using these

(x+4)(x+4)(x-6)

the equation passes through (2,36)

put x = 2

(2+4)(2+4)(2-6) = (6)*(6)*(-4)

which exceeds 36 so we product the equation with -1/4 to get 36

Final equation

y = \frac{-1}{4} (x+4)(x+4)(x-6)

  y  = \frac{-1}{4}( x^3 + 2x^2 - 32x -96)

3 0
2 years ago
I don't understand this quadratic functions question please help.
djyliett [7]
I think it would be b
6 0
3 years ago
Follow the process of completing the square to solve 2x2 + 8x - 12 = 0.
Rom4ik [11]
Please:  Use "^" to denote exponentiation:  <span>2x^2 + 8x - 12 = 0

Reduce this by div. every term by 2:             </span><span>x^2 + 4x - 6 = 0

Here a=1, b=4 and c = -6.  Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:

</span> x^2 + 4x +4  - 4 - 6 = 0.  Rewrite the square as (x+2)^2, obtaining new equation

(x+2)^2 = 10.  Take the sqrt of both sides:   x+2 = plus or minus sqrt(10).

Finally, solve for x:  x = -2 plus or minus sqrt(10).



8 0
3 years ago
2n-n-4+7n in simplest form
MrMuchimi
<span>2n-n-4+7n in simplest form is found by combining like terms:

(2-1+7)n - 4 = 8n-4, or 4(2n-1)</span>
6 0
3 years ago
Hey! please help i’ll give brainliest! if it lets me:)
lozanna [386]

Answer:

south since its the opposite

5 0
3 years ago
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