Answer:
y-1=5(x-3)
Step-by-step explanation:
y=mx+b where m=slope and b=y-intercept,
y-y1=m(x-x1)
y-1=5(x-3)
Answer:
2 bears in 2020.
Step-by-step explanation:
We have been given that a new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.
We will use exponential decay formula to solve our given problem as:
, where,
y = Final quantity,
a = Initial value,
r = Decay rate in decimal form,
x = Time
Upon substituting our given values in above formula, we will get:
, where x corresponds to year 2000.
To find the population in 2020, we will substitute 
in our equation as:
Therefore, 2 bears are there predicted to be in 2020.
Since population is decreasing so population is best described as exponential decay.
Answer: FG = 3x + 10
<u>Step-by-step explanation:</u>
EF + FG = EG <em>Segment Addition Postulate</em>
x-7 + FG = 4x+3 <em>Substitution</em>
-7 + FG = 3x + 3 <em>Subtraction Property of Equality</em>
FG = 3x + 10 <em>Addition Property of Equality</em>
Answer:
w => -4
w =<9
Step-by-step explanation:
Answer:
Step-by-step explanation:
3x – y + 2z = 6 - - - - - - - - - 1
-x + y = 2 - - - - - - - - - - - - -2
x – 2z = -5 - - - - - - - - - - - -3
From equation 2, x = y - 2
From equation 3, x = 2z - 5
Substituting x = y - 2 and x = 2z - 5 into equation 1, it becomes
3(y - 2) – y + 2z = 6
3y - 6 - y + 2z = 6
3y - y + 2z = 6 + 6
2y + 2z = 12 - - - - - - - - - 4
3(2z - 5) – y + 2z = 6
6z - 15 - y + 2z = 6
- y + 6z + 2z = 6 + 15
- y + 8z = 21 - - - - - - - - - - 5
Multiplying equation 4 by 1 and equation 5 by 2, it becomes
2y + 2z = 12
- 2y + 16z = 42
Adding both equations
18z = 54
z = 54/18 = 3
Substituting z = 3 into equation 5, it becomes
- y + 8×3 = 21
- y + 24 = 21
- y = 21 - 24 = - 3
y = 3
Substituting y = 3 into equation 2, it becomes
-x + 3 = 2
- x = 2 - 3 = -1
x = 1
