True or false, a line with slope 0 never passes through point (0,0)

The bricklayer bought 7500 bricks to brick a wall. He calculated that every horizontal layer of bricks will contain 321 bricks.

statuscvo [17]

There will be 23 layers of brick, because 7500/321 = 23 with 117 leftover.

6 0

3 years ago

A movie theater charges $10 for adult tickets and $7 for child tickets. On a particular day, they made $1446 in ticket sales. Th

luda_lava [24]

X = adults
Y = child

X+y=168
X=168-y

$10x + $7y = $1446

10(168-y) + 7y = 1446
1680 - 10y + 7y = 1446
-3 y = -234
Y = 78

X = 168-78
X = 90

$10*90 + $7*78 =
$900 + $546 = $1446

6 0

3 years ago

Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the a

ZanzabumX [31]

Answer:

1) Null hypothesis: $p\geq 0.41$

Alternative hypothesis: $p < 0.41$

2) $\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

3) $z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

4) $z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

5) $z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

7) Null hypothesis: $p\geq 0.41$

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

$p_o=0.41$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area: Null hypothesis:[tex]p\geq 0.41$

Alternative hypothesis: $p < 0.41$

Part 2

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

$z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

Part 5

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :

$z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

Part 6

We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

Part 7

Null hypothesis: $p\geq 0.41$

4 0

3 years ago

8.

mihalych1998 [28]

Answer

Secured

Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

What is the insverse of the function f(x) =2x+1?

goldenfox [79]

F(x) = 2x + 1

To find the inverse of a function you just need to switch the x by y or vice-versa:

-> y = 2x + 1
-> x = 2y + 1

After that you isolate the y again:

-> 2y = x - 1

-> y = (x-1)/2
-> f^-1 (x) = (x-1)/2

Answer:
$f^{ - 1} (x) = (x - 1) \div 2$

5 0

3 years ago