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timofeeve [1]
3 years ago
14

Expand (3x + 1)(x + 2) using the box method of by foiling. Show or explain your steps.

Mathematics
1 answer:
Reika [66]3 years ago
3 0
The result would be 3x^2+7x+2.

If you have any question, tell me and I would be more than happy to help! Thanks.
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The diameter of a circle is 10 meters. What is the area of the circle?(use 3.14 for pie and round to the nearest tenth
asambeis [7]

A=78.54

A=1 /4πd2=1 /4·π·10^2≈78.53982m²

Hope this helps

Formulas

A=πr2

d=2r

8 0
3 years ago
Help ! The answer is given but I need to explain how I got it
horsena [70]
Area ( If you know the circumference) :
C^2 / (4×3.14) Brackets are important!
So you have to type :
53.38^2/(4×3.14)
= 226.865
6 0
3 years ago
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what
cluponka [151]

<u>Problem</u>

A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?

<u>Work </u>

Probability = no. of favorable outcomes /total no. of outcomes

Probability of getting a blue marble=5/5+6+9=5/20

Probability of getting a red marble=6/20−1=6/19

5/20×6/19

<u>Answer</u>

3/20

So it is C.

4 0
3 years ago
Read 2 more answers
If you roll a 6-sided die 4 times, what is the probability of one roll being a multiple of 3? A)2/3 B)16/81 C)145/1296 D)65/81 E
DerKrebs [107]

Answer:

671/1296

The probability of rolling at least one six is therefore 1 − 625/1296 = 671/1296 ≈ . 517.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Derivative of this function<br> <br>Y= -7X³ -8X² +6X +3
zaharov [31]

In general, the derivative of a single term  Ax^(n)  is  A n x^(n-1) .

And the derivative of a sum of many terms is the sum of the derivatives
of the individual terms.  

Using these two rules, the derivative (with respect to 'x') of the expression
in the question is . . .

<em>            Y' = -21x² - 16x + 6</em>


7 0
3 years ago
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