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2 years ago

Challenge fr y'all. solve this to get 50 points and brainliest coming up if you get the right answer

Mathematics

2 answers:

Butoxors [25]2 years ago

5 0

Answer:

5 Hours and 12 k/m

Hope this helps :)

TEA [102]2 years ago

3 0

Answer:

See below

Step-by-step explanation:

Use the law of cosines:

$AB=\sqrt{PA^2+PB^2-2*PA*PB*cosP}$
$AB=\sqrt{60^2+100^2-2*60*100*cos80} =\sqrt{11516.22} =107.31$

ii)

Use the law of sines:

sin ∠A / PB = sin ∠P / AB
sin ∠A / 100 = sin 80 / 107.31
sin ∠A = 100 sin 80 deg / 107.31
sin ∠A = 0.92
∠A = arcsin 0.92
∠A = 67° (rounded)

iii)

Bearing of B from A:

90° + (67° - 30°) =
127°

PB is longer distance. Time to reach B:

t = d/s
t = 100/20 = 5 hours

The speed s of the slower ship:

s = d/t
s = 60/5 = 12 km/h

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3 years ago

A plane flying horizontally at an altitude of 1 mile and a speed of 510 mi/h passes directly over a radar station. Find the rate

sdas [7]

Answer:

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Step-by-step explanation:

Given

To properly solve this question, I illustrate some given parameters using attached image

From the image, apply Pythagoras theorem

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$2x\frac{dx}{dt} + 0 = 2y\frac{dy}{dt}$

$2x\frac{dx}{dt} = 2y\frac{dy}{dt}$

Divide both sides by 2

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From the question, we have that the plan travels are 510mi/h.

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Apply Pythagoras theorem

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$x^2 + 1 = 4$

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1 year ago

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If this helped you please rate

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