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grigory [225]
3 years ago
8

A coin bank contains only quarters and dimes. The total value of the coins in the bank is $8.80. If the dimes were quarters and

the quarters were dimes, the coins' total value would be $7.30. Find the number of dimes in the bank
PLEASE EXPLAIN ANSWER
Mathematics
1 answer:
masha68 [24]3 years ago
8 0

Answer:

  • 18 dimes

Step-by-step explanation:

Let the number of dimes be d and quarters be q

<u>The value is $8.80 = 880¢, so:</u>

  • 10d + 25q = 880 ⇒ 2d + 5q = 176

<u>If the dimes were quarters and the quarters were dimes, the coins' total value would be $7.30 or 730¢</u>

  • 25d + 10q = 730 ⇒ 5d + 2q = 146

<u>Now we have 2 equations. Solving the system by elimination, subtract 5 times the second equation from twice the first equation:</u>

  • 2(2d + 5q) - 5(5d + 2q) = 2(176) - 5(146)
  • 4d - 25d = -378
  • -21d = -378
  • d = -378/-21
  • d = 18
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We are given that a political study took a sample of 1300 voters in the town and found that 57% of the residents favored construction.

And, a political strategist wants to test the claim that the percentage of residents who favor construction is more than 54%, i.e;

Null Hypothesis, H_0 : p = 0.54 {means that the percentage of residents who favor construction is 54%}

Alternate Hypothesis, H_1 : p > 0.54 {means that the percentage of residents who favor construction is more than 54%}

The test statistics we will use here is;

                 T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } } ~ N(0,1)

where, p = actual percentage of residents who favor construction = 0.54

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So, Test statistics = \frac{0.57 -0.54}{\sqrt{\frac{0.57(1- 0.57)}{1300} } }

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