Question

Write an equation in slope-intercept form for the line that has the given slope and contains the point. Please show some work.( will mark brainliest)(4,-2)&(2,-1)

Answer 1

Answer:

An equation in the slope-intercept form will be:

$y=-\frac{1}{2}x+0$

Step-by-step explanation:

Given the points

• (4, -2)

• (2, -1)

Finding the slope between the points

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(4,\:-2\right),\:\left(x_2,\:y_2\right)=\left(2,\:-1\right)$

$m=-\frac{1}{2}$

We know that the slope-intercept form of the line equation is

$y=mx+b$

where m is the slope and b is the y-intercept.

substituting the values m=-1/2 and the point (4, -2) to determine the y-intercept i.e. 'b'.

$y=mx+b$

$-2=-\frac{1}{2}\left(4\right)+b$

$\frac{1}{2}\cdot \:4+b=-2$

$-2+b=-2$

$b=0$

Now, substituting the values b=0 and m=-1/2 to determine the equation in the slope-intercept form.

$y=mx+b$

$y=-\frac{1}{2}x+0$

Thus, an equation in the slope-intercept form will be:

$y=-\frac{1}{2}x+0$