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PolarNik [594]
3 years ago
8

Help me answer this q1

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
6 0

Answer: B is the answer yup B

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In a cookie jar,
Sedbober [7]

well, a WHOLE is 1, which we can split in many fractions, say 5/5, 10/10 or 999/999 and so on.

we know 1/5 of the jar is chocolate chip, and there's the rest, well, the Whole jar in 5ths have to be 5/5, if we take away 1/5 from 5/5, the "rest" is 5/5 - 1/5 = 4/5.

now, we also know that 1/2 of the "rest" is peanut butter, or namely that 1/2 of 4/5 is peanut butter, how much will that be?  let's divide 4/5 by 2

\cfrac{4}{5}\div 2\implies \cfrac{4}{5}\div \cfrac{2}{1}\implies \cfrac{4}{5}\cdot \cfrac{1}{2}\implies \cfrac{4}{10}\implies \cfrac{2}{5}

7 0
2 years ago
An angle measures 156° less than the measure of its supplementary angle. What is the measure of each angle?
GrogVix [38]

Answer:

12° and 168°

Step-by-step explanation:

If x is the angle, and y is the supplementary angle, then:

x + y = 180

x = y − 156

Solve the system of equations using substitution:

y − 156 + y = 180

2y = 336

y = 168

Plug back into either equation to find x:

x = 12

7 0
3 years ago
Read 2 more answers
X 3.6.PS-10 Question Help A new bank customer with $4,500 wants to open a money market account. The bank is offering a simple in
makkiz [27]
If it was in 10 years it would either be 2.6
4 0
3 years ago
Rename the number to 120,000 ten thousand
Ray Of Light [21]
120,000 renamed to ten thousand (10,000) is twelve ten thousand. Ten thousand in number form is 10,000.  When you divide 120,000 (one hundred and twenty thousand)  by 10,000 (ten thousand) you get 12.  120,000 (one hundred and twenty thousand)  /10,000 (ten thousand) = 12. So there are twelve ten thousands in 120,000.
4 0
3 years ago
In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :
Grace [21]

Answer:

See explanation

Step-by-step explanation:

In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.

Consider triangles DIH and EGH. In these triangles,

  • \angle DIH\cong \angle EGH as alternate interior angles;
  • \angle DHI\cong \angle GHE as vertical angles;
  • DH\cong HE because point H bisects segment DE (given).

Thus,

\triangle DIH\cong \triangle EGH by AAS postulate

4 0
3 years ago
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