Let's call the 13¢ stamps a and the 18¢ stamps b:
a+b = 42 and therefore a= 42-b (formula 1)
0.13a+0.18b= 6.66 In this formula, substitute the value of a according to formula 1:
0.13(42-b)+0.18b= 6.66 Multiply on the left to get rid of the parenthesis:
5.46-0.13b+0.18b= 6.66 Subtract 5.46 from both sides:
-0.13b+0.18b= 1.20 Add on the left:
0.05b= 1.20 Divide both sides by 0.05
b= 24 You have 24 18¢ stamps and:
42-24= 18 13¢ stamps
Check: (24 x 0.18) + (18 x 0.13)= 6.66 Correct.
The width would be 236 and the lengths would be 118
Use the equations 2L+W=472 and W*L=MAX
Change the first equation to W=472-2L and plug this into the other equation
(472-2L)(L)=MAX
472L-2L^2=M (take derivative)
472-4L=0 (set to 0 to find the max value)
4L=472
L=118
Plug into original to get W=236
Hope this helps!
Answer:idk
Step-by-step explanation:
idk
The values that make the denominator zero are not in the domain.
x²- 4x - 12 = 0
(x - 6)(x + 2) = 0
Answer: 6, -2
Answer:
x = -2
Step-by-step explanation:
These 2 angles are <u>alternate exterior</u> so they're equal to each other.
x + 127 = 125
x = 125 - 127
x = -2