The answer is x=3(y-2/3)
make me the brainliest answer please :)
3x + 3y + 6z = 9
2x + 1y + 3z = 7 ⇒ 6x + 6y + 8z = 6
1x + 2y - 1z = -10 6x + 6y + 8z = 6
4z = 12
3x + 3y + 6z = 9 4 4
2x + 1y + 3z = 7 ⇒ 0x + 0y + 4z = 12 z = 3
1x + 2y - 1z = -10 2x + y = -2
2x + (-4) = -2
2x - 4 = -2
+ 4 + 4
2x = 2
2 2
x = 1
(x, y, z) = (1, -4, 3)
From the equation we see that the center of the circle is at (-2,3) and the radius is 9.
So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...
d^2=(8--2)^2+(4-3)^2 and d^2=r^2=81 so
81=10^2+1^2
81=101 which is not true...
So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.
Thus the point lies outside or on the exterior of the circle...
To learn about circle from the given link
brainly.com/question/2166803
#SPJ4
Step-by-step explanation:
well first of all you have to expand the brackets. so 5(y+2)=4(x-3)
5y+10=4x-12
then you subtract 10
5y=4x-12-10=4x-22
then divide by 5 to get the value of y
y=(4x-22)/5
