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3 years ago

Can h help with this?

Mathematics

1 answer:

Setler [38]3 years ago

6 0

The Answer would be p(m)=25+10 because she started with a base pay of 10 dollars and the next lawn she charge 35 meaning it makes the rate of change 25

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Sixteen is seven plus three times a number find the number

Mama L [17]

Answer: x=3

Step-by-step explanation:

16 = 7 + 3x

9 = 3x

3 = x

4 0

3 years ago

Use the ratio test to determine whether the series is convergent or divergent.

Kitty [74]

Answer:

Divergent

Step-by-step explanation:

Given series has general term as

$\frac{2^n}{n^2}$

n+1 th term = $\frac{2^(n+1)}{(n+1)^2}$

WE have to check whether this series converges or diverges

Let us use ratio test

Ratio of n+1 th term to nth term

= $\frac{2n^2}{(n+1)^2} =\frac{2}{(1+\frac{1}{n} }^2$

by dividing numerator and denominator by n square

Take limits as n tends to infinity

The ratio tends to 2

Since ratio >2, the series diverges

4 0

4 years ago

Read 2 more answers

Work out the mean for data set below 3.2,5.4,4.3,3.7,5.9

lidiya [134]

The mean would be 4.5. This is because you add up all the numbers which equals 22.5. Then divide by 5 since there is 5 numbers in the set. So the answer comes out to be 4.5.

3 0

3 years ago

What is the product of the two matrices? Fill in the missing elements of the resulting matrix.

olganol [36]

The product of the given two matrices comes out to be $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Here we are given the 2 matrices as follows-

$\left[\begin{array}{ccc}7&-2\\-6&2\end{array}\right] \left[\begin{array}{ccc}1&1\\3&3.5\end{array}\right]$

To find the product of 2 matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix.

Here since both of the matrices are 2 × 2, their product is possible.

Now, to find the product, we need to multiply each element in the first row by each element of the 1st column of the second matrix and then find their sum. Similarly, we do this for all rows and columns.

Therefore,

$\left[\begin{array}{ccc}(7*1)+(-2*3)&(7*1)+(-2*3.5)\\(-6*1)+(2*3)&(-6*1)+(2*3.5)\end{array}\right]$