Answer:
DONT CARE I WISH u GET FAILED
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Answer:
49
Step-by-step explanation:
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Answer:
Step-by-step explanation:
To prove Δ ABC similar to ΔDBE we can consider
Segments AC and DE are parallel.
⇒ DE intersects AB and BC in same ratio.
AB is a transversal line passing AC and DE.
⇒∠BAC=∠BDE [corresponding angles]
Angle B is congruent to itself due to the reflexive property.
All of them are telling a relation of parts of ΔABC to ΔDBE.
The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".
Answer:
A
Step-by-step explanation:
on the left of the equation, (6^4)^-5 = 6^-20
the right side you add the exponents so it would be (-7-3) =-10
so it would be 6^-10, which is greater than 6^-20