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Gwar [14]
3 years ago
11

3/4 - 5/6 I will give brainliest if your answer is correct

Mathematics
2 answers:
Arada [10]3 years ago
5 0

\frac{3}{4}  -  \frac{5}{6}  \\  \\  =  >  \frac{3 - 5}{36}  \\  \\  =  >  \frac{ - 2}{36}  =  >  \frac{ - 1}{12} answer αηѕωєя

Sergio039 [100]3 years ago
4 0

Answer:

1/12 I think this is it if not sorry

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24 students and Jamall's class are wearing tennis shoes there are 30 students in his class tomorrow says that 70% of his class i
alexdok [17]
10% = 3
70% = 3 * 7
= 21 students

Jamall is wrong because 70% of the class = to 21 students.
5 0
3 years ago
Find the LCM of the numbers using prime factorizations<br> 18,45
andriy [413]

Answer:

90

Step-by-step explanation:

18:

18*1=18

18*2=36

18*3=54

18*4=72

18*5=90

18*6=108

45:

45*1=45

45*2=90

45*3=135

Therefore, 90 is the correct answer

5 0
3 years ago
A conical-shaped umbrella has a radius of 0.4 m and a height of 0.45 m. Calculate the amount of fabric needed to manufacture thi
GenaCL600 [577]

Answer:

0.76m²

Step-by-step explanation:

In the above question, we are given the following information.

Radius = 0.4m

Height = 0.45m

To solve this question, The umbrella is CONICAL in shape and it has no BASE, we would be finding the lateral surface area of a cone. Since we are given height and radius :

Lateral Surface Area of a cone =

πr√(h² + r²)

= π × 0.4√(0.45² + 0.4)

= 0.7566m²

≈ Approximately = 0.76m²

Therefore, the amount of fabric needed to manufacture this umbrella is 0.76m²

8 0
3 years ago
Multiply.<br> (3x + 1)(2x – 1)<br><br> Answer plz
DENIUS [597]

Answer:

= 3x + 1 + 2x - 1 \\  = 3x + 2x + 1 - 1 \\  = 5x + 0 \\  = 5x

8 0
4 years ago
Read 2 more answers
Please help!! 20 POINTS
rjkz [21]

f(-3) would be 36.

When looking at synthetic division, the numbers across the top represent the coefficients of x^2, x and the constant in that order. Therefore, the equation is as follows.

2x^2 - 5x + 3

Now we can put -3 into the equation and solve.

2(-3)^2 - 5(-3) + 3

2(9) + 15 + 3

18 + 15 + 3

36

7 0
3 years ago
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