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3 years ago

What is the solution to this equation?

Mathematics

2 answers:

____ [38]3 years ago

8 0

C is the solution x = 6

labwork [276]3 years ago

6 0

The solution to this equation is C (6)

3x - 3 = 15

3x = 15 + 3
3x = 18
3/3 x = 18/3

x = 6

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A ball is thrown vertically in the air with a velocity of 90ft/s. Use the projectile formula h=−16t2+v0t to determine at what ti

Debora [2.8K]

Answer:

$t=1.7 \ sec\ , t=4.0\ sec$

Step-by-step explanation:

<u>Vertical Throw</u>

It refers to a situation where an object is thrown verticaly upwards with some inicial speed v_o and let in free air (no friction) until it completes its movement up and finally returns to the very same point of lauch. The only acting force is gravity

The projectile formula is given as

$h=-16t^2+v_0t$

where t is time in seconds, h is the height in feet and v is the speed in ft/sec

We are required to find the time t where h=120 ft, knowing $v_o=90\ ft/sec$

$-16t^2+90t=120$

Rearranging

$-16t^2+90t-120=0$

This is a second-degree equation which will be solved with the formula

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\displaystyle x=\frac{-90\pm \sqrt{90^2-4(-16)(-120)}}{2(-16)}$

$\displaystyle x=\frac{-90\pm \sqrt{1380}}{-32}$

Two solutions are obtained

$\boxed{t=1.7 \ sec\ , t= 4.\ sec}$

Both solutions are possible because the ball actually is at 120 ft in its way up and then when going down

6 0

3 years ago

Read 2 more answers

Can someone help me please

Mrrafil [7]

Answer:
y = -1/2x + 14

3 0

3 years ago

How do I solve this?

Gennadij [26K]

The answer is 8a^3-27b^3

4 0

3 years ago

Let f(x)=x²+kx+4 and g(x)=x³+x²+kx+2k, where k is a real constant.

antoniya [11.8K]

The value of k such that the graph of f and the graph of g only intersect one is equal to 2.

The value of k such that the graph of f and the graph of g only intersect one is equal to 2. According to the image attached below, functions f(x) and g(x) intersect at point (x, y) = (0, 4) for k = 2.

<h3>How to find the value of the constant k of a system of two polynomic equations</h3>

Herein we have a system formed by two <em>nonlinear</em> equations, a <em>quadratic</em> equation and a <em>cubic</em> equation. Given the constraint that both function must only intersect once, we have the following expression:

f(x) - x² - k · x = 4 (1)

g(x) - x² - k · x = x³ + 2 · k (2)

x³ + 2 · k = 4

x³ + 2 · (k - 2) = 0

If f and g must intersect once, then the roots must of the form:

(x - r)³ = x³ + 2 · (k - 2)

x³ - 3 · r · x² + 3 · r² · x - r³ = x³ + 2 · (k - 2)

Then, the following conditions must be met: - 3 · r · x² = 0, 3 · r² · x = 0. If x may be any real number, then r must be zero and the value of k must be:

2 · (k - 2) = 0

k - 2 = 0

k = 2

Therefore, the value of k such that the graph of f and the graph of g only intersect one is equal to 2. According to the image attached below, functions f(x) and g(x) intersect at point (x, y) = (0, 4) for k = 2.

To learn more on polynomic functions: brainly.com/question/24252137

#SPJ1

7 0

2 years ago

On Thursday, a local hamburger shop sold a combined total of 282 hamburgers and cheeseburgers. The number of cheeseburgers sold

denpristay [2]

448, you just have to work the problem. But if my math is correct, then the answer is 448.

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3 years ago