Ask question

Ask question

All categories

vladimir2022 [97]

3 years ago

5

A sample of gas has a pressure of 100.0 KPa and 25C. Calculate the pressure if the temperature is changed to 125C while the volu

me remains constant.

1 answer:

atroni [7]3 years ago

6 0

Answer:

133.56kPa

Explanation:

Applying Pressure Law,

P/T = P'/T'....................... Equation 1

Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T' = Final Temperature.

From the question, we were asked to calculate P'

There, we make P' the subject of the equation

P' = PT'/T...................... Equation 2

Given: P = 100kPa, T = 25°C = (273+25) = 298K, T' = 125°C = (273+1250K = 398 K

Substitute these values into equation 2

P' = (100×398)/298

P' = 133.56kPa

Hence the pressure is 133.56kPa

You might be interested in

Express in scientific notation. Remember, M must be a number 1 ≤ M < 10. 0.000543 =

alexandr1967 [171]

The correct answer would be <span>5.43 x 10^-4</span>

7 0

3 years ago

Read 2 more answers

How many elements are there?

svlad2 [7]

Answer:

118 is your answer!

5 0

3 years ago

Read 2 more answers

True or false: In a chemical reaction, atoms of elements cannot be present in the products if they were not present in the react

Amanda [17]

Answer:

A

Explanation: Your answer is A true

8 0

3 years ago

Which of the following pairs of reactants is not correctly listed with its product solution? A. Strong acid-strong base reactant

gizmo_the_mogwai [7]

<span>It makes no difference which reactant is placed first, a strong acid combined stoichiometrically with a strong base will produce a neutral solution. Due to hydrolysis, a weak acid and strong base produce a basic solution when combined stoichiometrically, and a weak base and strong acid produce an acidic solution when combined stoichiometrically

Mark as brainlist please if correct! BTW have a blessed day!</span>

5 0

3 years ago

Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.

Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

$\%C_E = \frac{E}{T} * 100\%$

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In $(Ca(OH)_2)$

The amount of all elements is: (i.e formula mass of $(Ca(OH)_2)$ )

$T = 1 * Ca + 2 * H + 2 * O$

$T = 1 * 40 + 2 * 1 + 2 * 16$

$T = 74$

The amount of calcium is: (i.e formula mass of calcium)

$E = 1 * Ca$

$E = 1 * 40$

$E = 40$

So, the percentage component of calcium is:

$\%C_E = \frac{E}{T} * 100\%$

$\%C_E = \frac{40}{74} * 100\%$

$\%C_E = \frac{4000}{74}\%$

$\%C_E = 54.05\%$

The amount of hydrogen is:

$E = 2 * H$

$E = 2 * 1$

$E = 2$

So, the percentage component of hydrogen is:

$\%C_E = \frac{E}{T} * 100\%$

$\%C_E = \frac{2}{74} * 100\%$

$\%C_E = \frac{200}{74}\%$

$\%C_E = 2.70\%$

Similarly, for oxygen:

The amount of oxygen is:

$E = 2 * O$

$E = 2 * 16$

$E = 32$

So, the percentage component of oxygen is:

$\%C_E = \frac{E}{T} * 100\%$

$\%C_E = \frac{32}{74} * 100\%$

$\%C_E = \frac{3200}{74}\%$

$\%C_E = 43.24\%$

5 0

3 years ago