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Travka [436]
2 years ago
14

Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.

Chemistry
1 answer:
Colt1911 [192]2 years ago
5 0

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\%C_E = \frac{E}{T} * 100\%

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In (Ca(OH)_2)

The amount of all elements is: (i.e formula mass of (Ca(OH)_2))

T = 1 * Ca + 2 * H + 2 * O

T = 1 * 40 + 2 * 1 + 2 * 16

T = 74

The amount of calcium is: (i.e formula mass of calcium)

E = 1 * Ca

E = 1 * 40

E = 40

So, the percentage component of calcium is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{40}{74} * 100\%

\%C_E = \frac{4000}{74}\%

\%C_E = 54.05\%

The amount of hydrogen is:

E = 2 * H

E = 2 * 1

E = 2

So, the percentage component of hydrogen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{2}{74} * 100\%

\%C_E = \frac{200}{74}\%

\%C_E = 2.70\%

Similarly, for oxygen:

The amount of oxygen is:

E = 2 * O

E = 2 * 16

E = 32

So, the percentage component of oxygen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{32}{74} * 100\%

\%C_E = \frac{3200}{74}\%

\%C_E = 43.24\%

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The answer:
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6 0
2 years ago
How the calculation of the [OH-], pH and % ionization for 0.619 M ammonia (NH3) NH3 + H2O (liq) rightwards harpoon over leftward
fomenos

Answer:

[OH⁻] = 3.34x10⁻³M; Percent ionization = 0.54%; pH = 11.52

Explanation:

Kb of the reaction:

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Is:

Kb = 1.8x10⁻⁵ = [NH₄⁺] [OH⁻] / [NH₃]

<em>As all NH₄⁺ and OH⁻ comes from the same source we can write: </em>

<em>[NH₄⁺] = [OH⁻] = X</em>

<em>And as </em>[NH₃] = 0.619M

1.8x10⁻⁵ = [X] [X] / [0.619M]

1.11x10⁻⁵ = X²

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<h3>[OH⁻] = 3.34x10⁻³M</h3><h3 />

% ionization:

[NH₄⁺] / [NH₃] * 100 = 3.34x10⁻³M / 0.619M * 100 = 0.54%

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As pOH = -log [OH-]

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5 0
2 years ago
Is iornIInitrate ionic or covalent
kondaur [170]

Answer:

Iron (II) nitrate is ionic compound

Explanation:

Formula:

Fe(NO₃)₂

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Its molecular mass is 179.85 g/mol.

NO⁻₃ is anion while Fe⁺² is cation.

Iron loses its two electron which is accepted by nitrate.

Its molecular formula can be written as FeN₂O₆.

Its color is pale green.

Its melting point is 333.65 K.

It is para magnetic compound.

it is mostly present in non hydrated form.

It is also known as ferric nitrate.

It is used to form sodium amide.

Its is also used catalyst.

7 0
3 years ago
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8 0
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IrinaVladis [17]
The answer is 1.75 x 10¹⁰ m.
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Diameter of chlorine atom = </span><span>175 picometers (pm) 
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in scientific notation we will write </span>0.000000000175 m as <span>1.75 x 10</span>¹⁰ m
8 0
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