Answer:
2 real solutions
Step-by-step explanation:
We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:
b² - 4ac
If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.
Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:
b² - 4ac
(-20)² - 4 * 6 * 1 = 400 - 24 = 376
Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.
<em>~ an aesthetics lover</em>
Answer: 17.92
Step-by-step explanation:
32% of 56
Change to fraction
32 /100 x 56
Change to decimal
0.32 x 56
= 17.92
First, let's count:
there are 26 possible outcomes for E1 (black card)
there are 4x9 = 36 possible outcomes for E2, to pick a numbered card (any color)
there are 2x9 =18 possible outcomes for E1 (black) AND E2 (numbered, spade + clower)
the probability of E1 AND E2 is the ratio of the count of possible outcomes for E1 + E2 and the count of all possible outcomes (52 choices to pick a card from the deck):
P(E1 and E2) = 18/52 (34.6%)
And as asked:
P(E1) = 26/52 = 1/2 (50%)
P(E2) = 36/52 = 9/13 (69.2%)
