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Citrus2011 [14]
2 years ago
6

Someone help. Foundation

Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
4 0

Answer:

rotation of 90 degrees counterclockwise centered at the origin

Step-by-step explanation:

Just look at one single point of A and what must happen to it to become the corresponding point in B.

Look at point (2, 1) in figure A. Draw a segment from (0, 0) to (2, 1).

The corresponding point in figure B to (2, 1) is (-1, 2). Now draw a segment from (0, 0) to (-1, 2). Look at the relationship between the two segments.

The segment (0, 0) to (2, 1) is perpendicular to the segment (0, 0) to (-1, 2).

The transformation is a rotation of 90 degrees counterclockwise centered at the origin.

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Multiply 6√3 • 8√14 • √10 • √2
uranmaximum [27]

Answer:

96 sqrt(210)

Step-by-step explanation:

6√3 • 8√14 • √10 • √2

We multiply what is outside the square roots with what is outside the square roots  and what is inside the square roots with what is inside the square roots

6*8 = 48

3*14*10*2 = 840

6√3 • 8√14 • √10 • √2

48 sqrt(840)

48 sqrt( 4*210)

sqrt(a*b) = sqrt(a) sqrt(b)

48 sqrt(4) sqrt(210)

48 *2 sqrt(210)

96 sqrt(210)

210 is 3*7 *5*2  which are all primes, so we cannot simplify the sqrt (210)

7 0
3 years ago
Find the volume of the parallelepiped with adjacent edges PQ, PR, and PS. P(1, 0, −1), Q(3, 3, 0), R(3, −3, 0), S(1, −2, 2)
topjm [15]

Answer:

the volume of the parallelepiped is = 36  

Step-by-step explanation:

given,

P(1, 0, −1),      Q(3, 3, 0),      R(3, −3, 0),     S(1, −2, 2)

PQ = Q - P = (2, 3, 1)

PR = R - P  = (2, -3 , 1)

PS = S - P  = (0, -2 , 3)

now volume of parallelopiped

[PQ PR PS] = \begin{bmatrix}2 & 3 &1 \\ 2 & -3 &1 \\ 0 & -2 &3 \end{bmatrix}

now calculating determinant of the matrix

        = 2 (-9+2) -  3 (6-0) + 1 (-4-0)

        = -14  - 18  - 4

        = -36

hence , the volume of the parallelepiped is = 36  

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3 years ago
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frutty [35]

I think so....

4/3 that is the gradient

Answer = 1.5

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Step-by-step explanation:

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