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ziro4ka [17]
3 years ago
15

We can think of 3 ÷ 1/4 as the answer to the question “How many groups of 1/4 are in 3?” What is the answer to the question

Mathematics
1 answer:
OverLord2011 [107]3 years ago
5 0

Answer: 12

Step-by-step explanation: 3*4/1 = 12/1 =12

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Please answer them! be quick if you can, thank you.
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Answer:

Question one = 35a - 15

Question two = 9

Step-by-step explanation:

Distributive property means to multiply all the numbers inside the parenthesis

by the outside number. 5 x 7a equals 35a and 5 x 3 = 15.

35 x 9 - 315 - 15 = 300

A = 9

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2 years ago
The number u is doubled and the product is increased by 280
kherson [118]
(2u)+280 is the answer
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Alice works at a health care facility. She has measured the hemoglobin levels of 200 people. The data follows a normal distribut
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In normal distribution, 68% of the values are within +_ 1 SD. That leaves 32% outside that range. Thus, 32 people with greater than 13, 100 people greater than 14 (200*0.68/2+32)
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3 years ago
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drag the gray arrow so that it is pointing midway between horizontal and vertical, heading downward and toward the right. extend
alex41 [277]

The speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

A star moving away from the observer (say on Earth) will have its emitted light red-shifted (move to lower frequency), i.e., the spectrum moving to left if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving towards the observer (say on Earth) will have its emitted light blue-shifted (move to higher frequency), i.e., the spectrum moving to the right if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving perpendicular to the observer (say on Earth) will have its emitted light will no change with respect to the spectrum of the stationary star.

These are due to the Doppler effect, the equation of frequency detected by the observer as

f_o = f_s\sqrt{\frac{1-\beta }{1+\beta } } where \beta = \frac{v}{c}, v the relative velocity of the moving source (the star here), f^s is the frequency of light emitted by the source.

Hence the answer is the speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

To learn more about frequency click here brainly.com/question/26177128

#SPJ4

7 0
1 year ago
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