A data set has a median of 48, and six of the numbers in the data set are less than

Mathematics

2 answers:

nata0808 [166]3 years ago

4 0

Answer:

Step-by-step explanation:

n, n, n, n, n, n, 48, n, n, n, n, n, n

1, 2, 3, 4, 5, 6, 7, 8, 9, 10,11,12,13

Margarita [4]3 years ago

3 0

Pretty sure it’s b cus if u divide 48 by all the numbers given b is the only one without a decimal meaning 16 goes into 48

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A quadratic equation is written in four equivalent forms below.

____ [38]

IV is the most useful (even though all will work)
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6 0

3 years ago

If cos(θ) = 6/8 and θ is in the IV quadrant, then fine:

svetoff [14.1K]

Answer:

a) 1

b) $\frac{4}{3}$

c) = 1

Step-by-step explanation:

We are given the following in the question:

$\cos \theta = \dfrac{6}{8}$

θ is in the IV quadrant.

$\sin^2 \theta + \cos^2 \theta = 1\\\\\sin \theta = \sqrt{1-\dfrac{36}{64}} = -\dfrac{2\sqrt7}{8}\\\\\tan \theta = \dfrac{\sin \theta}{\cos \theta} = -\dfrac{2\sqrt7}{6}\\\\\csc \theta = \dfrac{1}{\sin \theta} = -\dfrac{8}{2\sqrt7}$