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Hunter-Best [27]
2 years ago
10

1. Are the polygons similar?

Mathematics
1 answer:
jeyben [28]2 years ago
3 0

The polygons are similar.

This is because dividing the corresponding sides forms the same ratio, as shown by the three equations below

35/28 = 1.25

25/20 = 1.25

(15.5)/(12.4) = 1.25

So the larger figure on the right has side lengths that are 1.25 times larger compared to the corresponding sides of the figure on the left.

You'll need to flip the figure on the left so that the side labeled "20" is along the top, and the "28" is along the bottom.

After this flip happens, also note that the angle arc markings match up. The bottom pairs of angles of each figure are shown with a single arc, while the top angles are shown as double arcs. This helps visually show which angles pair up and are congruent to one another.

Because we have similar proportions as discussed earlier, and congruent pairs of angles like this, this shows the two figures are similar quadrilaterals. The one on the right is simply an enlarged scaled up copy of the figure on the left.

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The measure of an angle is seventy-one times the measure of its supplementary angle. What is the measure of each angle?
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Answer:

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Step-by-step explanation:

So, remember if 2 angles are supplementary, they equal 180 degrees. Let's call the smaller angle x, meaning the bigger angle, which is 89 times the size of the smaller angle, would be 89x. Now let's put that into an equation.

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Now in order to determine x, we have to divide by 90 on both sides.

X= 2

So we know that the smaller angle is 2, meaning that if the larger angle is 89 times the size, the larger angle would be 178.

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Y is directly proportional to square root of x<br> If y=56 when x=49 find,<br> y when x=81
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\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{\begin{array}{llll} \textit{"y" directly}\\ \textit{proportional to }\sqrt{x} \end{array}}{y = k\sqrt{x}}\qquad \textit{we know that} \begin{cases} y = 56\\ x = 49 \end{cases}\implies 56=k\sqrt{49} \\\\\\ 56=7k\implies \cfrac{56}{7}=k\implies 8=k~\hfill \boxed{y=8\sqrt{x}} \\\\\\ \textit{when x = 81, what is "y"?}\hfill y=8\sqrt{81}\implies y=8(9)\implies y=72

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