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iris [78.8K]
3 years ago
8

is it possible to store a 20 foot long pipe in a rectangular room that is 10 feet by 12 feet by 8 feet?

Mathematics
2 answers:
Anastaziya [24]3 years ago
7 0
First we'll consider the floor size.
In a 10 by 12 room the longest pipe that will fit lying on the floor equals the hypotenuse of a 10 by 12 triangle:
hypotenuse² = 10² + 12²
hypotenuse² = 100 + 144
hypotenuse² = 244
hypotenuse = <span> <span> <span> 15.62 feet

Now we have to consider the third dimension (height = 8 feet).
The two sides would be 15.62 and 8
</span></span></span>hypotenuse² = 15.62² + 8²
hypotenuse² = 244 + 64 = 308
hypotenuse = 17.55
So, the longest pipe that would fit in that room would be 17.55 feet long.


EleoNora [17]3 years ago
6 0
No, if the pipe is 20 foot long that means the room would have be 20 foot long, tall, or wide which its not.
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Inequality- 5g+ 69.50= 85.

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<h3>How to determine the number</h3>

From the information given, we have can deduce that;

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