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denis23 [38]
3 years ago
5

Can someone pls help me. it’s marked as late work and i don’t understand how to do

Mathematics
1 answer:
scoray [572]3 years ago
4 0
So how you would answer this question is by finding the area of the sides. So the rectangle is 25 x 17 or 425 and there is 4 rectangles. You take the area of the rectangle and multiply it by 4, which would be 1700 and now you find the area of the square which is 17 x 17 or 289 and then you multiply that by 2 because there are two squares, 578 and you take that answer and put it with the area of the rectangles and you get your surface area. 2278 is the surface area of the rectangular prism. Another way to explain it is there are 6 sides so six areas and you just add the areas together to get the surface area. Hope this helps :D
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Help please and please give a detailed answer
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Working out:
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What is the solution to the equation? 1/2n + 3 = 6​
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Answer:

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Step-by-step explanation:

1/2n + 3 = 6

1/2n = 3

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Answer:

don't ask for an explanation. your answer is below.

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2 years ago
A computer manufacturing company has sent a mail survey to 2,800 of its randomly selected customers that have purchased a new la
vodka [1.7K]

Answer:

The 96% confidence interval for the population proportion of customers satisfied with their new computer is (0.77, 0.83).

Step-by-step explanation:

We have to calculate a 96% confidence interval for the proportion.

We consider the sample size to be the customers that responded the survey (n=800), as we can not assume the answer for the ones that did not answer.

The sample proportion is p=0.8.

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The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.8*0.2}{800}}\\\\\\ \sigma_p=\sqrt{0.0002}=0.014

The critical z-value for a 96% confidence interval is z=2.054.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=2.054 \cdot 0.014=0.03

Then, the lower and upper bounds of the confidence interval are:

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The 96% confidence interval for the population proportion is (0.77, 0.83).

4 0
3 years ago
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