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2 years ago

You have 40 quarters. You find 20% more quarters in your room. Then

Mathematics

1 answer:

Annette [7]2 years ago

8 0

Answers:

Expression for the total number of quarters is 40*1.20

Amount of money you have left is 6 dollars

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Explanation:

You start with 40 quarters. 20% of this is 0.20*40 = 8 which means you found 8 more quarters. The total goes from 40 to 40+8 = 48.

A slight shortcut is to write 40*1.20 = 48

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48 quarters = 48*0.25 = 12 dollars

Or you can divide by 4 to determine the total value of the quarters in dollars.

If you spent half (50%) of that money, then you'll be left with 6 dollars.

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Need help can someone help me with this question

REY [17]

In system A, the first equation multiply by 4

8x - 4y = 12 (1st)

3x + 4y = 10 (2nd)

--------------------add

11x = 22

So answer is B.

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3 years ago

Simplify 9 + 6k +3 +212 +3 +7

melisa1 [442]

Answer:

6k+234

Step-by-Step Explanation:

Add 9, 3, 212, 3, and 7. You get 234. You can't change 6k because the variable, so you end up with 6k+234.

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2 years ago

Read 2 more answers

Geometric Series assistance

Levart [38]

we have been asked to find the sum of the series

$\sum _{n=1}^5\left(\frac{1}{3}\right)^{n-1}$

As we know that a geometric series has a constant ratio "r" and it is defined as

$r=\frac{a_{n+1}}{a_n}=\frac{\left(\frac{1}{3}\right)^{\left(n+1\right)-1}}{\left(\frac{1}{3}\right)^{n-1}}=\frac{1}{3}$

The first term of the series is $a_1=\left(\frac{1}{3}\right)^{1-1}=1$

Geometric series sum formula is

$S_n=a_1\frac{1-r^n}{1-r}$

Plugin the values we get

$S_5=1\cdot \frac{1-\left(\frac{1}{3}\right)^5}{1-\frac{1}{3}}$

On simplification we get

$S_5=\frac{121}{81}$

Hence the sum of the given series is $\frac{121}{81}$

5 0

3 years ago

You have 6 green marbles, 23 blue marbles, and 18 red marbles. what is the probability of choosing a red marble. express your an

AysviL [449]

The probability of choosing a red marble is 18/47.

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3 years ago

The domain of the relation is

vladimir2022 [97]

The domain of a relation is the set of all the x-terms of the relation.

Let's look at an example.

In the image provided I have attached a relation and we want to list the domain.

So, I will list all the x-terms. Notice however that I listed 7 once even though it appears twice in the relation. When listing the domain, you don't repeat the x-terms.

5 0

3 years ago