The two consecutive integers are 21 and 22.
<h3>
How to find the two consecutive integers?</h3>
Two consecutive integer numbers can be written as x and x + 1.
The lesser of these two numbers is x, and we know that it is 10 more than one-half of the greater integer, then we can write:
x = 10 + (x + 1)/2
Now we can solve that equation for x:
x = 10 + (x + 1)/2
2x = 20 + (x + 1)
2x = 21 + x
x = 21
Then the lesser number is x = 21 and the larger number is x + 1 = 22
If you want to learn more about integer numbers:
brainly.com/question/2493629
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<span>cos x = [ e^(ix) - e^(-ix) ] / 2i along with [ A - B ]^5 =
( A^5 - B^5) - 5 AB ( A^3 - B^3) + 10 A²B² (A - B )...A = e^(ix) , B = e^(-ix)
[ cos x ] ^5 = (1/32i) { [ e^(5ix) - e^(-5x) ] - 5 [ ( e^(3ix) - e^(-3ix) ] + 10 [ e^(ix) - e^(-ix) ] }
= ( 1 / 16 ) { cos 5x - 5 cos 3x + 10 cos x }.....much faster</span>
Answer:
The answer is: 1/4 chance witch is 25% also
Step-by-step explanation: