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3 years ago

What graph represents a function?

Mathematics

1 answer:

vredina [299]3 years ago

4 0

Answer:

Bottom answer

Step-by-step explanation:

Although I cannot see the answer labels, the answer is the very bottom graph. The way you can find a functional graph is if you add vertical lines going down and that there is only one point that crosses it, not two. It is kind of difficult for me to explain, so if you need help, I suggest you look up how to know when a graph is a function or not.

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Find the slope of the line that passes through the following points: (5, 3) and (-2, -4)

Aleksandr [31]

Answer:

Step-by-step explanation:

To find the slope, you must subtract the second y axis from the first y axis then the second x axis from the first x axis.

Problem: (5, 3) (-2, -4)

Solution: Step 1. - 4 - 3 = 7 (subtract the second y axis from the first y axis)

Step 2. - 2 - 5 = 7 (subtract the second x axis from the first x axis)

Answer: 7/7

Final Answer: 1

Mark me as brainliest!!

6 0

3 years ago

Find the area.........

rodikova [14]

Answer:

211 cm

Step-by-step explanation:

upper rectangle + lower rectangle (11-8=3) + end triangles

(8x20) + (3x12) + (1/2x3x5 each x2)

160+36+15=211

3 0

2 years ago

Write the rules for determining the sign of the product when multiplying integers. Then, write the the rules for determining the

kondor19780726 [428]

For multiplication, if both integers have like signs, it is always positive. If they have unlike signs it is negative.
For division, if both integers have like signs it is positive. If they have unlike signs it is negative.

7 0

3 years ago

Ivan and 3 acrobats are matched up against a team of grandma's. The result is a tie the 2 sides are evenly matched. How many gra

Neporo4naja [7]

Answer:

Step-by-step explanation:

Ivan and 3 others were evenly matched.

1+3=4

So there were 4 grandmas on the other team. :)

4 0

2 years ago

Find the critical numbers sin^2x+cosx 0 < x< 2pi

ryzh [129]

$\bf sin^2(x)+cos(x)\iff [sin(x)]^2+cos(x)\\\\
-----------------------------\\\\
\cfrac{dy}{dx}=2sin(x)cos(x)-sin(x)\implies 0=2sin(x)cos(x)-sin(x)
\\\\\\
0=sin(x)[2cos(x)-1]\implies 
\begin{cases}
0=sin(x)\\
sin^{-1}(0)=\measuredangle x\\
\pi \\
----------\\
0=2cos(x)-1\\\\ \frac{1}{2}=cos(x)\\\\ cos^{-1}\left( \frac{1}{2} \right)=\measuredangle x\\\\ \frac{\pi }{3},\frac{5\pi }{3}
\end{cases}$

5 0

3 years ago