Given:
A number when divided by 780 gives remainder 38.
To find:
The reminder that would be obtained by dividing same number by 26.
Solution:
According to Euclis' division algorithm,
...(i)
Where, q is quotient and 
is the remainder.
It is given that a number when divided by 780 gives remainder 38.
Substituting 
in (i), we get
So, given number is in the form of 
, where q is an integer.
On dividing by 26, we get
Since q is an integer, therefore (30q+1) is also an integer but 
is not an integer. Here 26 is divisor and 12 is remainder.
Therefore, the required remainder is 12.
Answer:
x^3-6x^2-10x+100
Step-by-step explanation:
Step 1: Distribute x to (x²-6x+20).
x(x²-6x+20)=x^3-6x^2+20x
Step 2: Distribute 5 to (x²-6x+20).
5(x² − 6x + 20)=5x²-30x+100
Step 3: Combine x^3-6x^2+20x and 5x²-30x+100.
x^3-6x^2-10x+100
hope it helps you <3
The width of the laptop is 6 inches long.
Answer:14 hrs and 25 mins
Step-by-step explanation:
