The relationship between 3x+4y=1 and 6x+8y=2 is that they are parallel lines.
<h3>What is the slope-intercept form of an equation?</h3>
Any linear equation has the form of y=mx+b
m is the slope of the equation
b is the y-intercept
The easiest way to see the relationship between the two lines is to transform them both into slope-intercept form, which is y=mx+b.
Equation 1 can be rewritten as
3x+4y=1
4y=1-3x
y= ![\frac{1-3x}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1-3x%7D%7B4%7D)
Equation 2 can be rewritten as:
6x+8y=2
8y=2-6x
y = ![\frac{2-6x}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B2-6x%7D%7B8%7D)
Y= ![\frac{1-3x}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1-3x%7D%7B4%7D)
In this form, we can easily identify that both lines have a slope of
, but that they have different y-intercepts. Lines will equal slopes but different y-intercepts are parallel.
Therefore, the lines are parallel.
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185 plus the second number which is 196 plus 90 is 471
Answer:
all real numbers such that x is greater than or equal to 2 (x≥2)
Step-by-step explanation:
Value of cos(x+π) = ![\bold{\frac{\sqrt{3} }{2}}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D%7D)
Given cosine of x = ![-\frac{\sqrt{3} }{2}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D)
i.e., cos(x) = ![-\frac{\sqrt{3} }{2}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D)
Also cos(
) =
. So x =
.
We need to find cos(x+π) = cos(
).
But its value is not easy to find. So we use trigonometric formulas.
We have the trigonometric formula, cos (x+π) = - cos(x) = -
= ![\bold{\frac{\sqrt{3} }{2}}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D%7D)
Cos(x+π) lies in the 3rd quadrant. So there cosine has negative values. That is why, cos (x+π) = - cos(x).
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