Question

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 9N acts on a certain object, the acceleration of the object is 3 m/s2 . If the force is changed to 6N , what will be the acceleration of the object?

Answer 1

Answer:

The acceleration is 2m/s^2

Step-by-step explanation:

Given

Variation: Direction Variation

Represent Force with F and Acceleration with A

When

$F= 9N; A=3m/s^2$

Required

Find A when F =6N

The variation can be represented as:

$F \alpha A$

Convert to an equation

$F = kA$

Where

$k = variation\ constant$

When

$F= 9N; A=3m/s^2$

We have:

$9N = k * 3m/s^2$

Solve or k

$k = \frac{9N}{3m/s^2}$

$k = 3kg$

When

$F = 6N$

We have:

$F = kA$

Substitute 6N for F and 3kg for k

$6N = 3kg * A$

Solve for A

$A = \frac{6N}{3kg}$

$A = 2m/s^2$