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jeka94
3 years ago
8

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 9N acts on a

certain object, the acceleration of the object is 3 m/s2 . If the force is changed to 6N , what will be the acceleration of the object?
Mathematics
1 answer:
ikadub [295]3 years ago
6 0

Answer:

The acceleration is 2m/s^2

Step-by-step explanation:

Given

Variation: Direction Variation

Represent Force with F and Acceleration with A

When

F= 9N; A=3m/s^2

Required

Find A when F =6N

The variation can be represented as:

F \alpha A

Convert to an equation

F = kA

Where

k = variation\ constant

When

F= 9N; A=3m/s^2

We have:

9N = k * 3m/s^2

Solve or k

k = \frac{9N}{3m/s^2}

k = 3kg

When

F = 6N

We have:

F = kA

Substitute 6N for F and 3kg for k

6N = 3kg * A

Solve for A

A = \frac{6N}{3kg}

A = 2m/s^2

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