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Korolek [52]
3 years ago
8

How many integers $m$ are there such that $0

Mathematics
1 answer:
Alexandra [31]3 years ago
3 0

Answer:

I think you meant to put an attachment but I don't see one

Step-by-step explanation:

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Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
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balandron [24]

Answer:

A

Step-by-step explanation:

went up a positive 4 points:)

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Help me, please i im failing maath 41 f
antiseptic1488 [7]

Answer:

C

Step-by-step explanation:

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3(x-5) = 5x - (3 - x)
alina1380 [7]

Answer:

X=-4

Step-by-step explanation:

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-x-6y=10 x-2y=-2 using elimination?
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