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Nataliya [291]
3 years ago
8

Identify the slope of the line passing through the pair of points (5,2) and (-2,1). *(1point)

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer:

m= 1/7

Step-by-step explanation:

To solve for slope: y2- y1/ x2- x1 so,

1-2/ -2-5

= -1/ -7

= 1/7

iren2701 [21]3 years ago
8 0

Answer:

Slope is \frac{1}{7\\}.

Step-by-step explanation:

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777dan777 [17]

Answer:

24

Step-by-step explanation:

4 times 6 =24

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Amanda is 12 years old she has two sevens time as old as her father how many years ago was her father four times as old as Amand
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Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

7 0
4 years ago
Write an
Helga [31]

Answer:

Since the Line is Perpendicular

m.m'=-1

The line

y=x+8

Comparing with

Y=mx + C

m=1

m.m'=-1

m'=-1/m = -1/1 = -1.

y-y' = m'(x-x')

The point it passes is (-7,8)

y-8= -1(x--7)

y-8=-1(x+7)

y-8 = -x - 7

y + x -1 = 0.

or In Slope intercept Form

Just Make y the subject

y= -x + 1 ..... This is your answer.

Hope this helps!!!

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