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3 years ago

Identify the slope of the line passing through the pair of points (5,2) and (-2,1). *(1point)

Mathematics

2 answers:

olga nikolaevna [1]3 years ago

8 0

Answer:

m= 1/7

Step-by-step explanation:

To solve for slope: y2- y1/ x2- x1 so,

1-2/ -2-5

= -1/ -7

= 1/7

iren2701 [21]3 years ago

8 0

Answer:

Slope is $\frac{1}{7\\}$ .

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Amanda is 12 years old she has two sevens time as old as her father how many years ago was her father four times as old as Amand

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Ok so first I am assuming you ment 2 sevenths so 12 divided by 2 sevenths is 42. so the father is currently 42. so when she was 10 he was 40. since 10 is 4 times 40 that is the age we need. so 42 minus 40 is 2. therefore the answer is 2.

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3 years ago

Y=-x^2+6x-4 Find the Axis of Symmetry and the Vertex, Also solve the whole equation.

Inessa [10]

Answer:

1. Axis of symmetry: x = 3

2. Vertex: (3,5)

3. Solution of the equation:

x-intercepts:

$(3-\sqrt{5},0) \\\\(3+\sqrt{5},0)$

y-intercept: (0, -4)

Explanation:

1. Equation:

$y=-x^2+6x-4$

2. Axis of symmetry:

That is the equation of a parabola, whose standard form is:

$y=ax^2+bx+c$

Where:

$a=-1;b=6;c=-4$

The axis of symmetry is the vertical line with equation:

$x=-b/2a$

Substitute $a=-1,\text{ and }b=6$

$x=-6/[(2)(-1)]=-6/(-2)=3$

Thus, the axis of symmetry is:

$x=3$

3. Vertex

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

$y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5$

Therefore, the vertex is (3, 5)

4. Find the x-intercepts

The x-intercepts are the roots of the equation, which are the points wher y = 0.

$y=-x^2+6x-4=0$

Use the quadratic equation:

$x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}$

5. Find the y-intercept

The y-intercet is the value of y when x=0:

$y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4$

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4 years ago

Write an

Helga [31]

Answer:

Since the Line is Perpendicular

m.m'=-1

The line

y=x+8

Comparing with

Y=mx + C

m=1

m.m'=-1

m'=-1/m = -1/1 = -1.

y-y' = m'(x-x')

The point it passes is (-7,8)

y-8= -1(x--7)

y-8=-1(x+7)

y-8 = -x - 7

y + x -1 = 0.

or In Slope intercept Form

Just Make y the subject

y= -x + 1 ..... This is your answer.

Hope this helps!!!

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