Answer:
t(s) is in rejection zone then we reject H₀.
Bad weather indeed make apples weight decrease
Step-by-step explanation:
Normal Distribution
population mean μ₀ = 9.5 ou
sample size = n = 16 then we should apply t-student table
degree of fredom df = n - 1 df = 16 - 1 df = 15
1.-Test hypothesis
H₀ null hypothesis μ₀ = 9.5
Hₐ alternative hypothesis μ₀ < 9.5
One left tail-test
2.-Confidence level 95 %
α = 0,05 and df = 15 from t-student table we get t(c) = - 1.761
3.-Compute t(s)
t(s) = [ μ - μ₀ ] /√s/n t(s) = (9.32 - 9.5 )* √16 / 0.18
t(s) = - 0.18*√16 / 0.18
t(s) = - 4
4.-Compare t(s) and t(c)
t(s) < t(c) -4 < - 1.761
Then t(s) is in the rejection zone.
5.- Decision
t(s) is in rejection zone then we reject H₀.
Farmer conclude that bad weather make apples weight decrease
Answer:
0.4 of the chocolate bar.
Step-by-step explanation:
Answer:
Step-by-step explanation:
h(-1) = - 3|3(-1) - 6| - 3
h(-1) = - 3|-3 - 6| - 3
h(-1) = - 3|-9| - 3
h(-1) = - 3(9) - 3
h(-1) = - 27 - 3
h(-1) = - 30
