Answer;
The offsprings will be such that , a normal vision female, a heterozygous female, normal male and a colorblind male.
Explanation;
-Most X-linked traits in humans are recessive. One example of an X-linked trait is red-green colorblindness. Let (Xc) represent the recessive allele that causes colorblindness and (XC) represent the normal dominant allele. Females that are XCXC or XCXc have normal color vision, while XcXc females are colorblind. For males with; XcY are color blind, while those with XCY are have normal color vision.
Heterozygous female, XcXC
Normal male, XCY
The offspring of the parents, XcXC x XCY, are: XcXC (heterozygous female), XCXC( normal vision female), XCY (normal vision male), XcY (color blind male).
The answer is A. 0.54.
In a population p+q=1 (we have 2 alleles only).
The question states that 0.21 of the population(21%) have short legs meaning they are q^2.
So q=rad0.21=0.4582.
And p=1-q=0.5417.
Answer:
First, the options:
A. Midazolam
B. Ketamine
C. Nitrous Oxide
D. Bupivacaine
The ANSWER is A.
A. Midazolam
Explanation:
A. Midazolam✔
Midazolam is mainly used for amnesia or sedation in many diagnostic, therapeutic, and endoscopic activities or procedures.
B. Ketamine ❌
It has higher risk of side effects.
C. Nitrous oxide ❌
It won't be preferable for this case, since it can not be breathed in during a bronchoscopy.
D. Bupivacaine❌
This is solely for local anesthesia.
