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IgorC [24]
3 years ago
12

You randomly draw a marble from a bag, record its color, and then replace it. You draw a red marble 3 out of 20 times. What is t

he experimental
probability that the next marble will be red?
Mathematics
1 answer:
Aliun [14]3 years ago
8 0

Answer:

P(Red) = \frac{3}{20}

Step-by-step explanation:

Given

Red = 3

Trials = 20

Required

Determine the experimental probability of next marble being red

This is calculated as:

P(Red) = \frac{n(Red)}{Trials}

Substitute values for n(Red) and Trials

P(Red) = \frac{3}{20}

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Accuracy in taking orders at a drive-through window is important for fast-food chains. Periodically, QSR Magazine publishes "The
pav-90 [236]

Answer:

a) 0.7412 = 74.12% probability that all the three orders will be filled correctly.

b) 0.0009 = 0.09% probability that none of the three will be filled correctly

c) 0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d) 0.9991 = 99.91% probability that at least one of the three will be filled correctly

e) 0.0082 = 0.82% probability that only your order will be filled correctly

Step-by-step explanation:

For each order, there are only two possible outcomes. Either it is filled correctly, or it is not. Orders are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The percentage of orders filled correctly at Burger King was approximately 90.5%.

This means that p = 0.905

You and 2 friends:

So 3 people in total, which means that n = 3

a. What is the probability that all the three orders will be filled correctly?

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.905)^{3}.(0.095)^{0} = 0.7412

0.7412 = 74.12% probability that all the three orders will be filled correctly.

b. What is the probability that none of the three will be filled correctly?

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.905)^{0}.(0.095)^{3} = 0.0009

0.0009 = 0.09% probability that none of the three will be filled correctly.

c. What is the probability that one of the three will be filled correctly?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.905)^{1}.(0.095)^{2} = 0.0245

0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d. What is the probability that at least one of the three will be filled correctly?

This is

P(X \geq 1) = 1 - P(X = 0)

With what we found in b:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0009 = 0.9991

0.9991 = 99.91% probability that at least one of the three will be filled correctly.

e. What is the probability that only your order will be filled correctly?

Yours correctly with 90.5% probability, the other 2 wrong, each with 9.5% probability. So

p = 0.905*0.095*0.095 = 0.0082

0.0082 = 0.82% probability that only your order will be filled correctly

7 0
3 years ago
How does x/a = y/b I don't get it
grandymaker [24]
They are variables they can equal anything. it is just an example of two different fractions who's numbers are unknown.

3 0
3 years ago
A cube has volume 1200 cubic inches. Write the edge length of the cube as a power.
ludmilkaskok [199]
1200 is the domain the answer is times the domain
8 0
2 years ago
How to solve -2 2/5 subtract 7/10 <br> How to solve -3 subtract 1/10
galben [10]

Answer: 11

Step-by-step explanation:

275% × 4 =

(275 ÷ 100) × 4 =

(275 × 4) ÷ 100 =

1,100 ÷ 100 = 11

3 0
3 years ago
Read 2 more answers
Probability!
Reil [10]

Answer:

26/31

Step-by-step explanation:

N(B)=12

N(G)=14

N(Y)=5

N(S)=N(B)+N(G)+N(Y)

=12+14+5

=31

Now,

P(Not getting yellow)=N(B)+N(G)/N(S)

=12+14/31

=26/31

7 0
2 years ago
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