Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
Well what is 30x3 (because that is how you would find what is one third of unknown) then you find the answer witch is 90$
<span>The solution to the equation 2/3 A= -24 is the coordinate of point A.
2/3 A = -24
A = -24 / 2/3
A = -24 * 3/2
A = -72/2
A = -36
The solution to the equation 20=-b/0.5 is the coordinate of point B
20 = -b/0.5
20 * 0.5 = -b
10 = -b
10/-1 = -b/-1
-10 = b
A = -36 and B = -10
The distance between the two letters is 26 units. </span>
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:
10 1/2 sticks, or 11 sticks with half a stick left over.
Step-by-step explanation:
If every student (and there are 14 students) needs 3/4 stick of butter, the equation is 3/4 x 14 = 10 1/2
