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rusak2 [61]
4 years ago
7

5 2/3 +3 3/4= (Please also explain your thinking.) Thanks! :)

Mathematics
2 answers:
geniusboy [140]4 years ago
7 0
OKAY! So, this problem can also be written as 17/3 + 15/4. That can be converted to 64/12 + 45/12, which is 109/12. that is 9 and 1/12.
Fofino [41]4 years ago
6 0

Well you need to make 5 2/3 and 3 3/4 into improper fractions by doing the sum 3 x 5 + 2 over the original number. e.g 3 3/4 4 x 3 = 12 + 3 = 15  15/4

Do that for both and then add them together by creating the same bottom number (you can do this by multiplying the two bottom numbers) then add the top numbers but don't change the bottom numbers. 

17/3 +15/4

68/12 + 45/12 = 45 + 68 = 113/ 12

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Slope Intercept Form from 2 Points: (6,6) and (8,-8) "Show work"
JulsSmile [24]

Answer:

the desired equation is y = -7x + 48

Step-by-step explanation:

As we go from (6, 6) to (8, -8), x (the "run") increases by 2 while y (the "rise") increases by 14.  Thus, the slope is m = rise/run = -14/2 = -7.

The slope intercept form of the equation of a straight line is y = mx + b.  Here we need to find b.

y = mx + b becomes 6 = -7(6) + b, or 48 = b.

Thus, the desired equation is y = -7x + 48

4 0
4 years ago
One six-sided die and one sixteen-sided die are rolled. What is the probability of rolling an even number on the six-sided die a
RSB [31]

You have a 3/6 chance of getting even number (there are 3 even nunbers in the 6 die)

You have a 1/16 chance of getting a 16 on the other die

multiply them 1/3 × 1/16 then convert it to decimal form is your answer

5 0
3 years ago
Read 2 more answers
Which rule explains why these triangles are congruent?
mr_godi [17]
Dude where are the triangles
7 0
3 years ago
The quadratic equation 8x²+12x-14 has two real roots. What is the sum of the squares of these roots?
mars1129 [50]

Answer:

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

The sum of the squares of these roots is \frac{-3}{2}

Step-by-step explanation:

The given quadratic equation is 8x^2+12x-14 has two real roots.

To find the roots .

8x^2+12x-14=0

Dividing the above equation by 2

\frac{1}{2}(8x^2+12x-14)=\frac{0}{2}

4x^2+6x-7=0

For quadratic equation ax^2+bx+c=0 the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Where a and b are coefficents of x^2 and x respectively, c is a constant.

For given quadratic equation

a=4, b=6, c=-7

x=\frac{-6\pm\sqrt{6^2-4(4)(-7)}}{2(4)}

=\frac{-6\pm\sqrt{36+112}}{8}

=\frac{-6\pm\sqrt{148}}{8}

=\frac{-6\pm\sqrt{37\times 4}}{8}

=\frac{-6\pm\sqrt{37}\times\sqrt{4}}{8}

=\frac{-6\pm\sqrt{37}\times 2}{8}

=2\frac{(-3\pm\sqrt{37})}{8}

=\frac{-3\pm\sqrt{37}}{4}

x=\frac{(-3\pm\sqrt{37})}{4}

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

Now to find the sum of the squares of these roots

\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3+\sqrt{37}-3-\sqrt{37}}{4}

=\frac{-6}{4}

=\frac{-3}{2}

\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3}{2}

Therefore the sum of the squares of these roots is \frac{-3}{2}

3 0
3 years ago
Nojo King sells vacuum cleaners Each week he earns $200 plus 8% of his sales How much did he he earn last week if his sales tota
STALIN [3.7K]
200+0.08x
=200+0.08(3200)
=200+256
=$456. As a result, he earns total $456 last week. Hope it help!
3 0
3 years ago
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