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Luba_88 [7]
3 years ago
15

Find the Area of the Shaded Region.

Mathematics
1 answer:
agasfer [191]3 years ago
3 0

Answer:

I think it should be 32

Step-by-step explanation:

11 x 7= 77

9 x 5=45

77-45=32

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What is the length of the line segment with endpoints (8,−10) and (8, 20) ?
Gwar [14]
B is your answer because 20 - -10 is 10 brainliest please
4 0
3 years ago
Help me out please:)
stich3 [128]

Answer:

the answer is

(8.5,13.5)

5 0
3 years ago
I’m confused can ya help me
Harlamova29_29 [7]

Answer:

C & D

Step-by-step explanation:

x² + 3x - 3 = 0

a = co efficient of  x² = 1

b=  co efficient of x = 3

c = constant = -3

roots = (-b ± \sqrt{b-4ac})/2a

    = (-3±\sqrt{3^{2}-4*1*[-3]} )/2*1

    = (-3±\sqrt{9+12})/2

    = (-3±√21)/2

  x = \frac{-3+\sqrt{21}}{2}     ; x =\frac{-3-\sqrt{21}}{2}

7 0
3 years ago
Prove that an = 4^n + 2(-1)^nis the solution to
olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute a_n=4^n+2(-1)^n in the equation a_n=3a_{n-1}+4a_{n-2} the equality is true.

Let's substitute first in the right hand side:

3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})

Now we use the distributive laws. Also, note that (-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n} (this also works when the power is n-2).

=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}

=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}

=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n

then the sequence solves the recurrence relation.

4 0
3 years ago
What is equivalent to k/2​
Mazyrski [523]

Answer:

k x 1/2

Step-by-step explanation:

because k x 1/2 = k/2

8 0
3 years ago
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