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3 years ago

Find the Area of the Shaded Region.

Mathematics

1 answer:

agasfer [191]3 years ago

3 0

Answer:

I think it should be 32

Step-by-step explanation:

11 x 7= 77

9 x 5=45

77-45=32

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What is the length of the line segment with endpoints (8,−10) and (8, 20) ?

Gwar [14]

B is your answer because 20 - -10 is 10 brainliest please

4 0

3 years ago

Help me out please:)

stich3 [128]

Answer:

the answer is

(8.5,13.5)

5 0

3 years ago

I’m confused can ya help me

Harlamova29_29 [7]

Answer:

C & D

Step-by-step explanation:

x² + 3x - 3 = 0

a = co efficient of x² = 1

b= co efficient of x = 3

c = constant = -3

roots = (-b ± $\sqrt{b-4ac}$ )/2a

= (-3± $\sqrt{3^{2}-4*1*[-3]}$ )/2*1

= (-3± $\sqrt{9+12}$ )/2

= (-3±√21)/2

$x = \frac{-3+\sqrt{21}}{2} ; x =\frac{-3-\sqrt{21}}{2}$

7 0

3 years ago

Prove that an = 4^n + 2(-1)^nis the solution to

olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute $a_n=4^n+2(-1)^n$ in the equation $a_n=3a_{n-1}+4a_{n-2}$ the equality is true.

Let's substitute first in the right hand side:

$3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})$

Now we use the distributive laws. Also, note that $(-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n}$ (this also works when the power is n-2).

$=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}$

$=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}$

$=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n$

then the sequence solves the recurrence relation.

4 0

3 years ago

What is equivalent to k/2

Mazyrski [523]

Answer:

k x 1/2

Step-by-step explanation:

because k x 1/2 = k/2

8 0

3 years ago