Answer:
the actually answer is -8
Step-by-step explanation:
Let
x------> the <span>height of a cylinder
y------> the radius </span>of a cylinder
we know that
x=5y
[t<span>he lateral area of the cylinder]=[perimeter of the base]*height
</span>[perimeter of the base]=2*pi*r-------> 2*pi*y
[the lateral area of the cylinder]=[2*pi*y]*(5y)-----> 10*pi*y²
10*pi*y²=360*pi-----> y²=36--------> y=6 units
<span>
the answer is
</span><span>the length of the radius of the cylinder is 6 units</span><span>
</span>
The correct answer is 4 and 1/8
<span>Which strategy best explains how to solve this problem?
George entered his frog in a jumping contest. The frog jumped 2 feet the first jump. On the second jump, the frog jumped twice as far (4 feet). Each time the frog jumped, the jump doubled in length from its previous jump. How far did the frog jump on the 5th jump?</span><span><span><span> A.</span>Make a table.
In the first row, write 1st jump - 2 ft. In the next row, write 2nd jump - 2 ft. In the 3rd row, write 3rd jump - 2 ft. Continue this pattern until you get to the 5th jump. Then add the numbers in the right column to find the number of feet the frog jumped on the 5th jump.</span><span><span> B.</span>Draw a diagram.
Draw a line and label it 2 ft. Draw a line twice as long and label it 4 ft. Do this three more times. Keep doubling the distance each time to find how far the frog jumped on the 5th jump.</span><span><span> C.</span>Write a number sentence.
(2 × 5) + 2 + 4 = x
Multiply 2 inches by the 5th jump, then add the distances from the first and second jump. The answer is B:Draw a diagram. </span></span>
<span>Draw a line and label it 2 ft. Draw a line twice as long and label it 4 ft. Do this three more times. Keep doubling the distance each time to find how far the frog jumped on the 5th jump.</span>