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3 years ago

Will give branlist please answer this quickly.

Mathematics

2 answers:

Nady [450]3 years ago

5 0

I can’t see the second set of questions but I have answers for 1-8.
1. C- slope-intercept form
2. y= 3/4x - 4
3. y= 5x - 3
4. y= 1/2x - 2
5. -7
6. 2
7. C- slope: -2; y-int: 7
8. C- x=1

dmitriy555 [2]3 years ago

3 0

Answer:

I cant see good

Step-by-step explanation:

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nikitadnepr [17]

Part a: you would get 3x+4=22
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2 years ago

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crimeas [40]

Answer:

I'm pretty sure the answer is D.

Step-by-step explanation:

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3 years ago

X^2=3x+3 in standard form

weeeeeb [17]

Answer:

x^2-3x-3=0

Step-by-step explanation:

x^2=3x+3

x^2-3x-3=0

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3 years ago

Work out the surface area of this solid prism.<br> 29cm<br> 25cm<br> 20cm<br> 40cm<br> 36cm

dusya [7]

Is there a picture that goes with this?

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3 years ago

PLEASE HELP ME IVE POSTED THIS 765678 AND STILL NO RESPONSE

Debora [2.8K]

Problem 1

<h3>Answer: 6.7</h3>

----------------

Work Shown:

The two points are $(x_1,y_1) = (1,-2)$ and $(x_2,y_2) = (4,4)$

Apply the distance formula to get the following

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (-2-4)^2}\\\\d = \sqrt{(-3)^2 + (-6)^2}\\\\d = \sqrt{9 + 36}\\\\d = \sqrt{45}\\\\d \approx 6.7082039\\\\d \approx 6.7\\\\$

The distance between the two endpoints is roughly 6.7 units. This is the same as saying the segment is roughly 6.7 units long.

======================================================

Problem 2

<h3>Answer: 3.6</h3>

----------------

Work Shown:

We'll use the distance formula here as well.

This time we have the two points $(x_1,y_1) = (3,1)$ and $(x_2,y_2) = (5,-2)$

The distance between them is...

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (1-(-2))^2}\\\\d = \sqrt{(3-5)^2 + (1+2)^2}\\\\d = \sqrt{(-2)^2 + (3)^2}\\\\d = \sqrt{4 + 9}\\\\d = \sqrt{13}\\\\d \approx 3.6055513\\\\d \approx 3.6\\\\$

This distance is approximate.

5 0

2 years ago