How many seconds in 4.3 years?

You have a solid 7.00 gram mixture of sodium nitrate and silver nitrate. You add distilled water to dissolve the solids. Now you

olganol [36]

Answer:

Net ionic equation: Ag⁺(aq) + Cl⁻(aq) → AgCl(s)

44.9% as AgNO₃

Explanation:

When sodium nitrate, NaNO₃ and silver nitrate, AgNO₃ are dissolved in water, the Na⁺, NO₃⁻ and Ag⁺ ions are formed.

Then, the addition of NaCl (Na⁺ and Cl⁻) produce AgCl⁻ as precipitate. <em>The net ionic equation is:</em>

If 2.54g of AgCl are formed and represents the 95.9% of yield. The real amount of AgCl is:

2.54g AgCl * (100% / 95.9%) = 2.65g AgCl.

In moles (Molar mass AgCl = 143.32g/mol):

2.65g AgCl * (1mol / 143.32g) = 0.0185 moles of AgCl = Moles of AgNO₃

<em>Because all Ag comes from AgNO₃</em>

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Thus, the original mass of silver nitrate and its precentage is (Molar mass AgNO₃ = 169.87g/mol):

0.0185 moles AgNO₃ * (169.87g / mol) = 3.14g of AgNO₃

Percentage:

3.14g AgNO₃ / 7.00g * 100 =

3 0

3 years ago

Formula of sodium bicarbonate<br>please help me with this

Stels [109]

Answer:

NaHCO₃

Explanation:

Sodium bicarbonate (baking soda) is a chemical compound with the formula NaHCO₃.

5 0

3 years ago

Air containing 0.06% carbon dioxide is pumped into a room whose volume is 12,000 ft3. The air is pumped in at a rate of 3,000 ft

castortr0y [4]

Answer:

$A(t)=1.8+34.2*e^{-t}$

Explanation:

The concentration of CO2 in the room will be the amount of CO2 in the room at time t, divided by the volume of the room.

Let A(t) be the amount of CO2 in the room, in ft3 CO2.

The air entering the room is 3000 ft3/min with 0.06% concentrarion of CO2. That can be expressed as (3000*0.06/100)=1.8 ft3 CO2/min.

The mixture leaves at 3000 ft3/min but with concentration A(t)/V. We can express the amount of CO2 leaving the room at any time is A(t).

We can write this as a differential equation

$dA/dt=v_i-v_o=1.8-A$

We can rearrange and integrate

$dA/dt=v_i-v_o=1.8-A\\\\dA/(A-1.8)=-dt\\\\\int(dA/(A-1.8) = -\int dt\\\\ln(A-1.8)=-t+C\\\\A-1.8=e^{-t}* e^{C}=C*e^{-t}\\\\A=1.8+C*e^{-t}$

We also know that A(0) = 12000*(0.3/100)=36 ft3 CO2.

$A(0)=1.8+C*e^{-0}\\36=1.8+C*1\\C=34.2$

Then we have the amount A(t) as

$A(t)=1.8+34.2*e^{-t}$

5 0

3 years ago

Given the balanced equation: 2KClO3 -->2KCl + 3O2

RSB [31]

Answer:

Option a → 111.9 g

Explanation:

The reaction is this:

2KClO₃ → 2KCl + 3O₂

2 moles of chlorate decompose to 2 moles of chloride and 3 moles of oxygen. Ratio is 2:2.

If I use 1.5 moles of chlorate I'll get the same moles of chloride by the decomposition.

Let's convert the moles to mass: 1.5 mol . 74.6 g / 1mol = 11.9 g

6 0

3 years ago

What is parthenolide

vovangra [49]

Parthenolide is a sesquiterpene lactone which occurs naturally in the plant feverfew--highly concentrated in the flowers and fruit.

7 0

3 years ago