Answer:- 10.6 L.
Solution:- Temperature is not given in this problem so it must be constant and we know that at constant temperature, the volume of the gas is inversely proportional to it's pressure. It is Boyle's law.
The equation for this law is written as:
P stands for pressure and V stands for volume and the subscripts 1 and 2 are representing initial and final values.
Initial pressure is 845 mmHg, initial volume is 4.60 L. Final volume is 368 mmHg and it asks to calculate the final volume.
Let's plug in the values in the equation and solve it for final volume.
divide both sides by 368mmHg:
= 10.6 L
So, the gas is transferred to a container with a volume of 10.6 L.
Answer:
10.5L
Explanation:
The volume in this question can be calculated by using the formula for gas law equation as follows:
PV = nRT
Where;
P = pressure (atm)
V = volume (litres)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the provided information in this question:
P = 6.18 atm
V = ?
n = 2.35 moles
R = 0.0821 Latm/molK
T = 63°C = 63 + 273 = 336K
Using PV = nRT
V = nRT/P
V = 2.35 × 0.0821 × 336/ 6.18
V = 64.83/6.18
V = 10.49
V = 10.5L
Answer:
Explanation:
Ground state electron configuration of potassium (K) is 1s2 2s2 2p6 3s2 3p6 4s1. The valency of the element is determined by electron configuration in the excited state. This electron configuration shows that the last shell of the potassium atom has an unpaired electron (4s1). So the valency of potassium is 1.