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Artyom0805 [142]
2 years ago
6

Assume a branch instruction bne $t1, $t2, Label is located in 0x00001840 in the instruction memory. The 16-bits branch address i

s 0x000C, If the branch is taken, what will be the new Program Counter (PC) value?
a. 0x00001844
b. 0x00001850
c. 0x00001870
d. 0x00001874
Computers and Technology
1 answer:
Ilia_Sergeevich [38]2 years ago
8 0

Answer:

a. 0x00001844

Explanation:

When the branch is takes the new program counter value is increased by 1. The value of existing memory is labelled with number sets and then next instruction is accepted in sequence. The new value is the increase in the current labelled value.

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#include <stdio.h>

#include <string.h>

#include <ctype.h>

 

struct detail

{

   char word[20];

   int freq;

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int update(struct detail [], const char [], int);

 

int main()

{

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   for (i = 0; i < 10; i++)

   {

      s[i].freq = 0;

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   printf("Enter string: ");

   i = 0;

   do

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       c = getchar();

       string[i++] = c;

 

   } while (c != '\n');

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   int i;

 

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