Answer:
congruent
Step-by-step explanation:
<em>5</em><em>X</em><em>+</em><em>1</em><em>3</em><em>+</em><em>X</em><em>+</em><em>5</em><em>=</em><em>9</em><em>0</em><em>°</em><em>(</em><em>SUM</em><em> </em><em>OF</em><em> </em><em>COMPLEMENTRY</em><em> </em><em>ANGLE</em><em> </em><em>IS</em><em> </em><em>EQUAL</em><em> </em><em>TO</em><em> </em><em>9</em><em>0</em><em>°</em><em>)</em>
<em>6</em><em>+</em><em>1</em><em>8</em><em>=</em><em>9</em><em>0</em><em>°</em>
<em>6</em><em>X</em><em>=</em><em>9</em><em>0</em><em>°</em><em>-</em><em>1</em><em>8</em><em>°</em>
<em>X</em><em>=</em><em>7</em><em>2</em><em>°</em><em>/</em><em>6</em>
<em>X</em><em>=</em><em>1</em><em>2</em><em> </em><em>°</em><em>ANSWER</em>
Answer:
Option D
Step-by-step explanation:
Given expression has been given as,
![\sqrt[5]{224x^{11}y^8}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B224x%5E%7B11%7Dy%5E8%7D)
![\sqrt[5]{224x^{11}y^8}=\sqrt[5]{2\times 2\times 2\times 2\times 2\times 7(x^{11})(y^8)}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B224x%5E%7B11%7Dy%5E8%7D%3D%5Csqrt%5B5%5D%7B2%5Ctimes%202%5Ctimes%202%5Ctimes%202%5Ctimes%202%5Ctimes%207%28x%5E%7B11%7D%29%28y%5E8%29%7D)
![=\sqrt[5]{(2^5)\times (7)(x^{10}\times x)(y^5\times y^3)}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B5%5D%7B%282%5E5%29%5Ctimes%20%287%29%28x%5E%7B10%7D%5Ctimes%20x%29%28y%5E5%5Ctimes%20y%5E3%29%7D)


![=2x^2y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=%3D2x%5E2y%5Csqrt%5B5%5D%7B7xy%5E3%7D)
Option D will be the answer.
Answer: 37
Step-by-step explanation:
87 x 2 = 174
248 - 174 = 74
74 divided by 2 = 37
So, therefore you answer will be 37
:))
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5