Over which interval(s) is the function decreasing?
Part A.
Using the Pythagorean theorem,
PR² = PQ² +QR²
PR² = (14 ft)² +(6 ft)² = 196 ft² +36 ft² . . . . substitute the given numbers
PR² = 232 ft² . . . . . . . . . . . . . . . . . . . . . . . .find the sum
PR = √(232 ft²) ≈ 15.23 ft . . . . . . . . . . . . . take the square root
The length of rod PR is 15.23 ft.
Part B.
Using the Pythagorean theorem,
PR² = PQ² +QR²
(16 ft)² = (14 ft)² +QR² . . . . . . . substitute the given numbers
256 ft² -196 ft² = QR² . . . . . .. subtract 14²
60 ft² = QR² . . . . . . . . . . . . . . find the sum
√(60 ft²) = QR ≈ 7.75 ft . . . . . take the square root
The new height QR is about 7.75 ft.
Answer:
A
Step-by-step explanation:
Answer: B
Step-by-step explanation: SAS: Side, Angle, Side SSS: Side, Side, Side AA: Equilateral Triangle
Answer:
Step-by-step explanation:
Givens
C = 12 * pi
C = 2*pi * r
Solution
2*pi * r = 12*pi Divide both sides by 2pi
2*pi * r/ 2*pi = 12*pi/2pi
r = 6
Answer: the diameter = 2 * r
the diameter = 12
