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svp [43]
3 years ago
6

Find the smallest number by which the number108 must be multiplied to obtain a perfect cube

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

2

Step-by-step explanation:

108*2

=216

216

=6^3

PLS GIVE BRAINLIEST

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kirill115 [55]

Answer:

C

Step-by-step explanation:

I don't know how to explain it, but i did the math and that is what i got, i'm sorry if it is incorrect. Hope this helps :3

3 0
3 years ago
Thirty three different video games showing violence were observed. The duration times of violence ​(in seconds) were recorded. W
AlladinOne [14]

Answer:

The "df" stands for "degrees of freedom", and represents the number of independent observations in a set of data.

Its value in this case is df=32.

Step-by-step explanation:

The sample is of size n=33.

As we do not know the population's standard deviation, we use as estimate the sample's standard deviation. Because of this, we use the t-statistic in place of the z-value.

The "df" stands for "degrees of freedom", and represents the number of independent observations in a set of data (the data in this case is the sample of 33 video games).

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df=N-1=33-1=32  

6 0
4 years ago
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Nataly_w [17]

Answer:

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10.5

Step-by-step explanation:

8 0
3 years ago
What is the measure of Angle A?
Marysya12 [62]

Answer:

136

Step-by-step explanation:

The sum of interior angles of a polygon is (n-2)x180 where n is the no. of sides. Here n=5 Therefore sum of int. angles = (3-2)x180= 3x180=540.

Sum of all given angles =404.

Remaining angle= 540-404=136

3 0
3 years ago
Read 2 more answers
Look at the attachment<br>Simplified it too <br>pls take it seriously ​
Phantasy [73]

\\ \rm\rightarrowtail \dfrac{sin(180+A)+2cos(180+A).cos(A-180)}{2cos^2(360+A)-cos(-A)}

\\ \rm\rightarrowtail \dfrac{-sinA+2(cos^2A-sin^2A)}{2cos^2A-cosA}

\\ \rm\rightarrowtail \dfrac{-sinA+2cos^2A-2sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA+2-2sin^2A-2sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA-4sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA(4sinA-1)}{cosA(2cosA-1)}

\\ \rm\rightarrowtail -tanA\left(\dfrac{4sinA-1}{2cosA-1}\right)

5 0
2 years ago
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