When one side of a quadrilateral is not to be fenced (ex. a river, as in this case), the optimal fencing to maximize the area is always to use half the fencing for the length, and one-fourth for each of the two widths
A) For 1000 ft of fencing which is to be used to cover 1 length and 2 widths:
L = 1000/2 = 500, and W = 1000/4 = 250. The optimal dimensions will be 250 x 500 ft.
B) This will result in an area of 250*500 = 125,000 sq. ft.
Answer:
x=4
Step-by-step explanation:
go it right on edge
Six point four minus three x plus eight...
Hope it works... not sure if it asked for that, I’d put that unless explained otherwise
Good luck!
Answer:
Step-by-step explanation:
A
Answer:
63 inches per tablecloth.
Step-by-step explanation:
35 / 20 = 1.75 yards per tablecloth,
= 1.75 * 36
= 63 inches.
